{"id":3601,"date":"2024-04-01T10:23:43","date_gmt":"2024-04-01T03:23:43","guid":{"rendered":"https:\/\/www.sqlservertutorial.net\/?page_id=3601"},"modified":"2024-04-01T10:25:19","modified_gmt":"2024-04-01T03:25:19","slug":"sql-server-count-distinct","status":"publish","type":"page","link":"https:\/\/www.sqlservertutorial.net\/sql-server-aggregate-functions\/sql-server-count-distinct\/","title":{"rendered":"SQL Server COUNT DISTINCT"},"content":{"rendered":"\n<p><strong>Summary<\/strong>: in this tutorial, you will learn how to use the SQL Server <code>COUNT DISTINCT<\/code> to get the total number of unique values in a column of a table.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id='introduction-to-the-sql-server-count-distinct'>Introduction to the SQL Server COUNT DISTINCT <a href=\"#introduction-to-the-sql-server-count-distinct\" class=\"anchor\" id=\"introduction-to-the-sql-server-count-distinct\" title=\"Anchor for Introduction to the SQL Server COUNT DISTINCT\">#<\/a><\/h2>\n\n\n\n<p>In SQL Server, the <code>COUNT()<\/code> function is an <a href=\"https:\/\/www.sqlservertutorial.net\/sql-server-aggregate-functions\/\">aggregate function<\/a> that returns the total number of rows that meet a certain condition.<\/p>\n\n\n\n<p>Sometimes, you may want to count the number of distinct values in a column that meets a condition. To do that, you can use the <code>DISTINCT<\/code> option:<\/p>\n\n\n<pre class=\"wp-block-code\" aria-describedby=\"shcb-language-1\" data-shcb-language-name=\"SQL (Structured Query Language)\" data-shcb-language-slug=\"sql\"><span><code class=\"hljs language-sql\">COUNT(DISTINCT column_name)<\/code><\/span><small class=\"shcb-language\" id=\"shcb-language-1\"><span class=\"shcb-language__label\">Code language:<\/span> <span class=\"shcb-language__name\">SQL (Structured Query Language)<\/span> <span class=\"shcb-language__paren\">(<\/span><span class=\"shcb-language__slug\">sql<\/span><span class=\"shcb-language__paren\">)<\/span><\/small><\/pre>\n\n\n<p>The <code>COUNT DISTINCT<\/code> will count duplicate values as one. It&#8217;s important to note that the <code>COUNT(DISTINCT)<\/code> function completely ignores <code>NULL<\/code> when counting.<\/p>\n\n\n\n<p>In practice, you often use the <code>COUNT DISTINCT<\/code> to get the total number of unique values in a column that satisfies a certain condition.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id='sql-server-count-distinct-examples'>SQL Server COUNT DISTINCT examples <a href=\"#sql-server-count-distinct-examples\" class=\"anchor\" id=\"sql-server-count-distinct-examples\" title=\"Anchor for SQL Server COUNT DISTINCT examples\">#<\/a><\/h2>\n\n\n\n<p>Let&#8217;s explore some examples of using the SQL Server <code>COUNT DISTINCT<\/code>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\" id='1-basic-sql-server-count-distinct-example'>1) Basic SQL Server COUNT DISTINCT example <a href=\"#1-basic-sql-server-count-distinct-example\" class=\"anchor\" id=\"1-basic-sql-server-count-distinct-example\" title=\"Anchor for 1) Basic SQL Server COUNT DISTINCT example\">#<\/a><\/h3>\n\n\n\n<p>First, <a href=\"https:\/\/www.sqlservertutorial.net\/sql-server-basics\/sql-server-create-table\/\">create a new table<\/a> called <code>numbers<\/code> that has an <code>id<\/code> column:<\/p>\n\n\n<pre class=\"wp-block-code\" aria-describedby=\"shcb-language-2\" data-shcb-language-name=\"SQL (Structured Query Language)\" data-shcb-language-slug=\"sql\"><span><code class=\"hljs language-sql\"><span class=\"hljs-keyword\">CREATE<\/span> <span class=\"hljs-keyword\">TABLE<\/span> numbers(\n   <span class=\"hljs-keyword\">id<\/span> <span class=\"hljs-built_in\">INT<\/span>\n);<\/code><\/span><small class=\"shcb-language\" id=\"shcb-language-2\"><span class=\"shcb-language__label\">Code language:<\/span> <span class=\"shcb-language__name\">SQL (Structured Query Language)<\/span> <span class=\"shcb-language__paren\">(<\/span><span class=\"shcb-language__slug\">sql<\/span><span class=\"shcb-language__paren\">)<\/span><\/small><\/pre>\n\n\n<p>Second, <a href=\"https:\/\/www.sqlservertutorial.net\/sql-server-basics\/sql-server-insert-multiple-rows\/\">insert some rows<\/a> into the <code>numbers<\/code> table:<\/p>\n\n\n<pre class=\"wp-block-code\" aria-describedby=\"shcb-language-3\" data-shcb-language-name=\"SQL (Structured Query Language)\" data-shcb-language-slug=\"sql\"><span><code class=\"hljs language-sql\"><span class=\"hljs-keyword\">INSERT<\/span> <span class=\"hljs-keyword\">INTO<\/span> numbers(<span class=\"hljs-keyword\">id<\/span>) \n<span class=\"hljs-keyword\">VALUES<\/span> \n  (<span class=\"hljs-number\">1<\/span>), \n  (<span class=\"hljs-number\">2<\/span>), \n  (<span class=\"hljs-number\">3<\/span>), \n  (<span class=\"hljs-number\">3<\/span>), \n  (<span class=\"hljs-literal\">NULL<\/span>), \n  (<span class=\"hljs-literal\">NULL<\/span>);<\/code><\/span><small class=\"shcb-language\" id=\"shcb-language-3\"><span class=\"shcb-language__label\">Code language:<\/span> <span class=\"shcb-language__name\">SQL (Structured Query Language)<\/span> <span class=\"shcb-language__paren\">(<\/span><span class=\"shcb-language__slug\">sql<\/span><span class=\"shcb-language__paren\">)<\/span><\/small><\/pre>\n\n\n<p>The <code>numbers<\/code> table has duplicate values 3 and <code>NULL<\/code>.<\/p>\n\n\n\n<p>Third, use the <code>COUNT DISTINCT<\/code> to return the total number of distinct values in the <code>id<\/code> column:<\/p>\n\n\n<pre class=\"wp-block-code\" aria-describedby=\"shcb-language-4\" data-shcb-language-name=\"SQL (Structured Query Language)\" data-shcb-language-slug=\"sql\"><span><code class=\"hljs language-sql\"><span class=\"hljs-keyword\">SELECT<\/span> \n  <span class=\"hljs-keyword\">COUNT<\/span>(<span class=\"hljs-keyword\">DISTINCT<\/span> <span class=\"hljs-keyword\">id<\/span>) \n<span class=\"hljs-keyword\">FROM<\/span> \n  numbers;<\/code><\/span><small class=\"shcb-language\" id=\"shcb-language-4\"><span class=\"shcb-language__label\">Code language:<\/span> <span class=\"shcb-language__name\">SQL (Structured Query Language)<\/span> <span class=\"shcb-language__paren\">(<\/span><span class=\"shcb-language__slug\">sql<\/span><span class=\"shcb-language__paren\">)<\/span><\/small><\/pre>\n\n\n<p>Output:<\/p>\n\n\n<pre class=\"wp-block-code\" aria-describedby=\"shcb-language-5\" data-shcb-language-name=\"SQL (Structured Query Language)\" data-shcb-language-slug=\"sql\"><span><code class=\"hljs language-sql\">id_count\n<span class=\"hljs-comment\">-----------<\/span>\n3<\/code><\/span><small class=\"shcb-language\" id=\"shcb-language-5\"><span class=\"shcb-language__label\">Code language:<\/span> <span class=\"shcb-language__name\">SQL (Structured Query Language)<\/span> <span class=\"shcb-language__paren\">(<\/span><span class=\"shcb-language__slug\">sql<\/span><span class=\"shcb-language__paren\">)<\/span><\/small><\/pre>\n\n\n<p>In this example, the query returns 3 which includes the numbers 1, 2, and 3. It counts the duplicate number 3 as 1 and ignores the <code>NULL<\/code>.<\/p>\n\n\n\n<p>In the upcoming examples, we&#8217;ll use the <code>production.products<\/code> and <code>production.brands<\/code> tables from the <a href=\"https:\/\/www.sqlservertutorial.net\/getting-started\/sql-server-sample-database\/\">sample database<\/a>:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"456\" height=\"169\" src=\"https:\/\/www.sqlservertutorial.net\/wp-content\/uploads\/products-brands.png\" alt=\"SQL Server COUNT DISTINCT Sample Tables\" class=\"wp-image-143\" srcset=\"https:\/\/www.sqlservertutorial.net\/wp-content\/uploads\/products-brands.png 456w, https:\/\/www.sqlservertutorial.net\/wp-content\/uploads\/products-brands-300x111.png 300w\" sizes=\"auto, (max-width: 456px) 100vw, 456px\" \/><\/figure>\n\n\n\n<h3 class=\"wp-block-heading\" id='2-counting-distinct-values-in-a-column'>2) Counting distinct values in a column <a href=\"#2-counting-distinct-values-in-a-column\" class=\"anchor\" id=\"2-counting-distinct-values-in-a-column\" title=\"Anchor for 2) Counting distinct values in a column\">#<\/a><\/h3>\n\n\n\n<p>The following example uses the <code>COUNT DISTINCT<\/code> to get the total number of model years in the <code>production.products<\/code> table:<\/p>\n\n\n<pre class=\"wp-block-code\" aria-describedby=\"shcb-language-6\" data-shcb-language-name=\"SQL (Structured Query Language)\" data-shcb-language-slug=\"sql\"><span><code class=\"hljs language-sql\"><span class=\"hljs-keyword\">SELECT<\/span> \n  <span class=\"hljs-keyword\">COUNT<\/span>(<span class=\"hljs-keyword\">DISTINCT<\/span> model_year) model_year_count \n<span class=\"hljs-keyword\">FROM<\/span> \n  production.products;<\/code><\/span><small class=\"shcb-language\" id=\"shcb-language-6\"><span class=\"shcb-language__label\">Code language:<\/span> <span class=\"shcb-language__name\">SQL (Structured Query Language)<\/span> <span class=\"shcb-language__paren\">(<\/span><span class=\"shcb-language__slug\">sql<\/span><span class=\"shcb-language__paren\">)<\/span><\/small><\/pre>\n\n\n<p>Output:<\/p>\n\n\n<pre class=\"wp-block-code\" aria-describedby=\"shcb-language-7\" data-shcb-language-name=\"SQL (Structured Query Language)\" data-shcb-language-slug=\"sql\"><span><code class=\"hljs language-sql\">model_year_count\n<span class=\"hljs-comment\">----------------<\/span>\n4<\/code><\/span><small class=\"shcb-language\" id=\"shcb-language-7\"><span class=\"shcb-language__label\">Code language:<\/span> <span class=\"shcb-language__name\">SQL (Structured Query Language)<\/span> <span class=\"shcb-language__paren\">(<\/span><span class=\"shcb-language__slug\">sql<\/span><span class=\"shcb-language__paren\">)<\/span><\/small><\/pre>\n\n\n<p>The output indicates that the <code>production.products<\/code> table has four unique model year values.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\" id='3-counting-distinct-values-with-a-condition'>3) Counting distinct values with a condition <a href=\"#3-counting-distinct-values-with-a-condition\" class=\"anchor\" id=\"3-counting-distinct-values-with-a-condition\" title=\"Anchor for 3) Counting distinct values with a condition\">#<\/a><\/h3>\n\n\n\n<p>The following example uses the <code>COUNT DISTINCT<\/code> to get the total number of model years that are greater than 2017 from the <code>production.products<\/code> table:<\/p>\n\n\n<pre class=\"wp-block-code\" aria-describedby=\"shcb-language-8\" data-shcb-language-name=\"SQL (Structured Query Language)\" data-shcb-language-slug=\"sql\"><span><code class=\"hljs language-sql\"><span class=\"hljs-keyword\">SELECT<\/span> \n  <span class=\"hljs-keyword\">COUNT<\/span>(<span class=\"hljs-keyword\">DISTINCT<\/span> model_year) model_year_count \n<span class=\"hljs-keyword\">FROM<\/span> \n  production.products \n<span class=\"hljs-keyword\">WHERE<\/span> \n  model_year &gt; <span class=\"hljs-number\">2017<\/span>;<\/code><\/span><small class=\"shcb-language\" id=\"shcb-language-8\"><span class=\"shcb-language__label\">Code language:<\/span> <span class=\"shcb-language__name\">SQL (Structured Query Language)<\/span> <span class=\"shcb-language__paren\">(<\/span><span class=\"shcb-language__slug\">sql<\/span><span class=\"shcb-language__paren\">)<\/span><\/small><\/pre>\n\n\n<p>Output:<\/p>\n\n\n<pre class=\"wp-block-code\" aria-describedby=\"shcb-language-9\" data-shcb-language-name=\"SQL (Structured Query Language)\" data-shcb-language-slug=\"sql\"><span><code class=\"hljs language-sql\">model_year_count\n<span class=\"hljs-comment\">----------------<\/span>\n2<\/code><\/span><small class=\"shcb-language\" id=\"shcb-language-9\"><span class=\"shcb-language__label\">Code language:<\/span> <span class=\"shcb-language__name\">SQL (Structured Query Language)<\/span> <span class=\"shcb-language__paren\">(<\/span><span class=\"shcb-language__slug\">sql<\/span><span class=\"shcb-language__paren\">)<\/span><\/small><\/pre>\n\n\n<p>In this example:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>First, include only products whose model years are greater than 2017 using the <code><a href=\"https:\/\/www.sqlservertutorial.net\/sql-server-basics\/sql-server-where\/\">WHERE<\/a><\/code> clause.<\/li>\n\n\n\n<li>Second, count the distinct model year of the filtered rows.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\" id='4-using-count-distinct-with-the-group-by-clause-example'>4) Using COUNT DISTINCT with the GROUP BY clause example <a href=\"#4-using-count-distinct-with-the-group-by-clause-example\" class=\"anchor\" id=\"4-using-count-distinct-with-the-group-by-clause-example\" title=\"Anchor for 4) Using COUNT DISTINCT with the GROUP BY clause example\">#<\/a><\/h3>\n\n\n\n<p>The following example uses the <code>COUNT DISTINCT<\/code> to obtain the total number of model years for each brand name:<\/p>\n\n\n<pre class=\"wp-block-code\" aria-describedby=\"shcb-language-10\" data-shcb-language-name=\"SQL (Structured Query Language)\" data-shcb-language-slug=\"sql\"><span><code class=\"hljs language-sql\"><span class=\"hljs-keyword\">SELECT<\/span>\r\n  brand_name,\r\n  <span class=\"hljs-keyword\">COUNT<\/span>(<span class=\"hljs-keyword\">DISTINCT<\/span> model_year) distinct_model_year\r\n<span class=\"hljs-keyword\">FROM<\/span>\r\n  production.products p\r\n  <span class=\"hljs-keyword\">INNER<\/span> <span class=\"hljs-keyword\">JOIN<\/span> production.brands b <span class=\"hljs-keyword\">ON<\/span> b.brand_id = p.brand_id\r\n<span class=\"hljs-keyword\">GROUP<\/span> <span class=\"hljs-keyword\">BY<\/span>\r\n  brand_name\r\n<span class=\"hljs-keyword\">ORDER<\/span> <span class=\"hljs-keyword\">BY<\/span>\r\n  brand_name;<\/code><\/span><small class=\"shcb-language\" id=\"shcb-language-10\"><span class=\"shcb-language__label\">Code language:<\/span> <span class=\"shcb-language__name\">SQL (Structured Query Language)<\/span> <span class=\"shcb-language__paren\">(<\/span><span class=\"shcb-language__slug\">sql<\/span><span class=\"shcb-language__paren\">)<\/span><\/small><\/pre>\n\n\n<p>Output:<\/p>\n\n\n<pre class=\"wp-block-code\" aria-describedby=\"shcb-language-11\" data-shcb-language-name=\"SQL (Structured Query Language)\" data-shcb-language-slug=\"sql\"><span><code class=\"hljs language-sql\">brand_name   | distinct_model_year\n<span class=\"hljs-comment\">-------------+------------------<\/span>\nElectra      | 3\nHaro         | 1\nHeller       | 2\nPure Cycles  | 1\nRitchey      | 1\nStrider      | 1\nSun Bicycles | 1\nSurly        | 3\nTrek         | 4\n(9 rows)<\/code><\/span><small class=\"shcb-language\" id=\"shcb-language-11\"><span class=\"shcb-language__label\">Code language:<\/span> <span class=\"shcb-language__name\">SQL (Structured Query Language)<\/span> <span class=\"shcb-language__paren\">(<\/span><span class=\"shcb-language__slug\">sql<\/span><span class=\"shcb-language__paren\">)<\/span><\/small><\/pre>\n\n\n<p>In this example:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><a href=\"https:\/\/www.sqlservertutorial.net\/sql-server-basics\/sql-server-joins\/\">Join<\/a> the <code>production.products<\/code> table with the <code>production.brands<\/code> table using the values in the <code>brand_id<\/code> column.<\/li>\n\n\n\n<li>Group the rows by brand names using the <code>GROUP BY<\/code> clause.<\/li>\n\n\n\n<li>Count the distinct model year for each brand name using the <code>COUNT DISTINCT<\/code>.<\/li>\n\n\n\n<li>Sort the groups by the brand names using <code>ORDER BY<\/code> clause.<\/li>\n<\/ul>\n\n\n\n<h2 class=\"wp-block-heading\" id='summary'>Summary <a href=\"#summary\" class=\"anchor\" id=\"summary\" title=\"Anchor for Summary\">#<\/a><\/h2>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Use the <code>COUNT DISTINCT<\/code> to count unique values in a column of a table.<\/li>\n<\/ul>\n<div class=\"helpful-block-content\" 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