{"id":1749,"date":"2018-11-12T20:30:21","date_gmt":"2018-11-12T13:30:21","guid":{"rendered":"http:\/\/www.sqlitetutorial.net\/?page_id=1749"},"modified":"2024-04-16T10:12:05","modified_gmt":"2024-04-16T03:12:05","slug":"sqlite-percent_rank","status":"publish","type":"page","link":"https:\/\/www.sqlitetutorial.net\/sqlite-window-functions\/sqlite-percent_rank\/","title":{"rendered":"SQLite PERCENT_RANK() Function"},"content":{"rendered":"\n<p><strong>Summary<\/strong>: in this tutorial, you will learn how to use the SQLite <code>PERCENT_RANK()<\/code> function to calculate the percent rank of a row in an ordered result set.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">Introduction to the PERCENT_RANK() function<\/h2>\n\n\n\n<p>The <code>PERCENT_RANK()<\/code> is a <a href=\"https:\/\/www.sqlitetutorial.net\/sqlite-window-functions\/\">window function<\/a> that calculates the percent rank of a given row using the following formula:<\/p>\n\n\n<pre class=\"wp-block-code\" aria-describedby=\"shcb-language-1\" data-shcb-language-name=\"SQL (Structured Query Language)\" data-shcb-language-slug=\"sql\"><span><code class=\"hljs language-sql\">(r - 1) \/ (the number of rows in the window or partition - r)<\/code><\/span><small class=\"shcb-language\" id=\"shcb-language-1\"><span class=\"shcb-language__label\">Code language:<\/span> <span class=\"shcb-language__name\">SQL (Structured Query Language)<\/span> <span class=\"shcb-language__paren\">(<\/span><span class=\"shcb-language__slug\">sql<\/span><span class=\"shcb-language__paren\">)<\/span><\/small><\/pre>\n\n\n<p>where <code>r<\/code> is the rank of the current row.<\/p>\n\n\n\n<p>The <code>PERCENT_RANK()<\/code> function returns a value that ranges from 0 to 1. The first row in any set has the percent rank of 0.<\/p>\n\n\n\n<p>Here is the syntax of the <code>PERCENT_RANK()<\/code> function:<\/p>\n\n\n<pre class=\"wp-block-code\" aria-describedby=\"shcb-language-2\" data-shcb-language-name=\"SQL (Structured Query Language)\" data-shcb-language-slug=\"sql\"><span><code class=\"hljs language-sql\">PERCENT_RANK()  \n    OVER ( \n        &#91;PARTITION BY partition_expression]\n        &#91;ORDER BY order_list]\n    )<\/code><\/span><small class=\"shcb-language\" id=\"shcb-language-2\"><span class=\"shcb-language__label\">Code language:<\/span> <span class=\"shcb-language__name\">SQL (Structured Query Language)<\/span> <span class=\"shcb-language__paren\">(<\/span><span class=\"shcb-language__slug\">sql<\/span><span class=\"shcb-language__paren\">)<\/span><\/small><\/pre>\n\n\n<p>In this syntax:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">()<\/h3>\n\n\n\n<p>The <code>PERCENT_RANK()<\/code> function takes no argument. However, empty parentheses are required.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">&nbsp;PARTITION BY<\/h3>\n\n\n\n<p>The <code>PARTITION BY<\/code> clause divides the rows into partitions to which the function applies. The <code>PARTITION BY<\/code> clause is optional. If you omit the <code>PARTITION BY<\/code> clause, the function will treat the whole result set as a single partition.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">&nbsp;ORDER BY<\/h3>\n\n\n\n<p>The <code>ORDER BY<\/code> clause specifies the order of rows in each partition to which the function applies. The <code>ORDER BY<\/code> clause is also optional. If you skip it, the function will return zero for all rows.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">SQLite PERCENT_RANK() function example<\/h2>\n\n\n\n<p>We will use the following&nbsp;<code>tracks<\/code> table&nbsp;from the <a href=\"https:\/\/www.sqlitetutorial.net\/sqlite-sample-database\/\">sample database<\/a> for the demonstration.<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img loading=\"lazy\" decoding=\"async\" width=\"174\" height=\"224\" src=\"https:\/\/www.sqlitetutorial.net\/wp-content\/uploads\/2018\/11\/tracks.png\" alt=\"\" class=\"wp-image-1558\"\/><\/figure>\n\n\n\n<h3 class=\"wp-block-heading\">1) Using PERCENT_RANK() function over the query result set<\/h3>\n\n\n\n<p>The following statement uses the <code>PERCENT_RANK()<\/code>function to find the percent rank of each track&#8217;s length within the album id 1:<\/p>\n\n\n<pre class=\"wp-block-code\" aria-describedby=\"shcb-language-3\" data-shcb-language-name=\"SQL (Structured Query Language)\" data-shcb-language-slug=\"sql\"><span><code class=\"hljs language-sql\"><span class=\"hljs-keyword\">SELECT<\/span>\n    <span class=\"hljs-keyword\">Name<\/span>,\n    Milliseconds,\n    <span class=\"hljs-keyword\">PERCENT_RANK<\/span>() <span class=\"hljs-keyword\">OVER<\/span>( \n        <span class=\"hljs-keyword\">ORDER<\/span> <span class=\"hljs-keyword\">BY<\/span> Milliseconds \n    ) LengthPercentRank\n<span class=\"hljs-keyword\">FROM<\/span>\n    tracks \n<span class=\"hljs-keyword\">WHERE<\/span>\n    AlbumId = <span class=\"hljs-number\">1<\/span>;\n<\/code><\/span><small class=\"shcb-language\" id=\"shcb-language-3\"><span class=\"shcb-language__label\">Code language:<\/span> <span class=\"shcb-language__name\">SQL (Structured Query Language)<\/span> <span class=\"shcb-language__paren\">(<\/span><span class=\"shcb-language__slug\">sql<\/span><span class=\"shcb-language__paren\">)<\/span><\/small><\/pre>\n\n\n<p>Here is the output:<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img loading=\"lazy\" decoding=\"async\" width=\"489\" height=\"226\" src=\"https:\/\/www.sqlitetutorial.net\/wp-content\/uploads\/2018\/11\/SQLite-PERCENT_RANK-with-ORDER-BY-clause.png\" alt=\"SQLite PERCENT_RANK with ORDER BY clause\" class=\"wp-image-1752\" srcset=\"https:\/\/www.sqlitetutorial.net\/wp-content\/uploads\/2018\/11\/SQLite-PERCENT_RANK-with-ORDER-BY-clause.png 489w, https:\/\/www.sqlitetutorial.net\/wp-content\/uploads\/2018\/11\/SQLite-PERCENT_RANK-with-ORDER-BY-clause-300x139.png 300w\" sizes=\"auto, (max-width: 489px) 100vw, 489px\" \/><\/figure>\n\n\n\n<p>To make the output more readable, you can use the <code>printf()<\/code> function to format the percent ranks:<\/p>\n\n\n<pre class=\"wp-block-code\" aria-describedby=\"shcb-language-4\" data-shcb-language-name=\"SQL (Structured Query Language)\" data-shcb-language-slug=\"sql\"><span><code class=\"hljs language-sql\"><span class=\"hljs-keyword\">SELECT<\/span>\n    <span class=\"hljs-keyword\">Name<\/span>,\n    Milliseconds,\n    printf(<span class=\"hljs-string\">'%.2f'<\/span>,<span class=\"hljs-keyword\">PERCENT_RANK<\/span>() <span class=\"hljs-keyword\">OVER<\/span>( \n        <span class=\"hljs-keyword\">ORDER<\/span> <span class=\"hljs-keyword\">BY<\/span> Milliseconds \n    )) LengthPercentRank\n<span class=\"hljs-keyword\">FROM<\/span>\n    tracks \n<span class=\"hljs-keyword\">WHERE<\/span>\n    AlbumId = <span class=\"hljs-number\">1<\/span>;\n<\/code><\/span><small class=\"shcb-language\" id=\"shcb-language-4\"><span class=\"shcb-language__label\">Code language:<\/span> <span class=\"shcb-language__name\">SQL (Structured Query Language)<\/span> <span class=\"shcb-language__paren\">(<\/span><span class=\"shcb-language__slug\">sql<\/span><span class=\"shcb-language__paren\">)<\/span><\/small><\/pre>\n\n\n<p>The output is as follows:<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img loading=\"lazy\" decoding=\"async\" width=\"488\" height=\"225\" src=\"https:\/\/www.sqlitetutorial.net\/wp-content\/uploads\/2018\/11\/SQLite-PERCENT_RANK-example.png\" alt=\"SQLite PERCENT_RANK example\" class=\"wp-image-1751\" srcset=\"https:\/\/www.sqlitetutorial.net\/wp-content\/uploads\/2018\/11\/SQLite-PERCENT_RANK-example.png 488w, https:\/\/www.sqlitetutorial.net\/wp-content\/uploads\/2018\/11\/SQLite-PERCENT_RANK-example-300x138.png 300w\" sizes=\"auto, (max-width: 488px) 100vw, 488px\" \/><\/figure>\n\n\n\n<h3 class=\"wp-block-heading\">2) Using PERCENT_RANK() function over the partitions<\/h3>\n\n\n\n<p>The following statement uses the <code>PERCENT_RANK()<\/code> function to calculate the percent rank of the track&#8217;s size in each album:<\/p>\n\n\n<pre class=\"wp-block-code\" aria-describedby=\"shcb-language-5\" data-shcb-language-name=\"SQL (Structured Query Language)\" data-shcb-language-slug=\"sql\"><span><code class=\"hljs language-sql\"><span class=\"hljs-keyword\">SELECT<\/span>\n  AlbumId,\n  <span class=\"hljs-keyword\">Name<\/span>,\n  <span class=\"hljs-keyword\">Bytes<\/span>,\n  printf  (\n    <span class=\"hljs-string\">'%.2f'<\/span>,\n    <span class=\"hljs-keyword\">PERCENT_RANK<\/span>() <span class=\"hljs-keyword\">OVER<\/span> (\n      <span class=\"hljs-keyword\">PARTITION<\/span> <span class=\"hljs-keyword\">BY<\/span>\n        AlbumId\n      <span class=\"hljs-keyword\">ORDER<\/span> <span class=\"hljs-keyword\">BY<\/span>\n        <span class=\"hljs-keyword\">Bytes<\/span>\n    )\n  ) SizePercentRank\n<span class=\"hljs-keyword\">FROM<\/span>\n  tracks;<\/code><\/span><small class=\"shcb-language\" id=\"shcb-language-5\"><span class=\"shcb-language__label\">Code language:<\/span> <span class=\"shcb-language__name\">SQL (Structured Query Language)<\/span> <span class=\"shcb-language__paren\">(<\/span><span class=\"shcb-language__slug\">sql<\/span><span class=\"shcb-language__paren\">)<\/span><\/small><\/pre>\n\n\n<p>The following picture shows the output:<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img loading=\"lazy\" decoding=\"async\" width=\"497\" height=\"304\" src=\"https:\/\/www.sqlitetutorial.net\/wp-content\/uploads\/2018\/11\/SQLite-PERCENT_RANK-with-PARTITION-BY-example.png\" alt=\"SQLite PERCENT_RANK with PARTITION BY example\" class=\"wp-image-1750\" srcset=\"https:\/\/www.sqlitetutorial.net\/wp-content\/uploads\/2018\/11\/SQLite-PERCENT_RANK-with-PARTITION-BY-example.png 497w, https:\/\/www.sqlitetutorial.net\/wp-content\/uploads\/2018\/11\/SQLite-PERCENT_RANK-with-PARTITION-BY-example-300x184.png 300w\" sizes=\"auto, (max-width: 497px) 100vw, 497px\" \/><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\">Summary<\/h2>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Use the <code>PERCENT_RANK()<\/code> function to calculate the percent rank of a row in an ordered result set.<\/li>\n<\/ul>\n<div class=\"helpful-block-content\" data-title=\"\">\n\t<header>\n\t\t<div class=\"wth-question\">Was this tutorial helpful 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