Dual View Random Solved Random Open
2 solved out of 3 shown (show only solved or open or formalised or unformalised)
SOLVED This has been resolved in some other way than a proof or disproof.
Let $\epsilon>0$. Is there a constant $C_\epsilon$ such that, for all large $n$, every graph on $n$ vertices with at least $n^{1+\epsilon}$ edges must contain a subgraph on at most $C_\epsilon$ vertices which is non-planar?
Erdős [Er71] writes it is 'not difficult to see' that $C_\epsilon\to \infty$ as $\epsilon\to 0$.

This was solved in the affirmative by Kostochka and Pyber [KoPy88], who proved that $G$ must contain a subdivision of $K_5$ (which is non-planar) with $O_\epsilon(1)$ many vertices.

View the LaTeX source

External data from the database - you can help update this
Formalised statement? No (Create a formalisation here)
Likes this problem None
Interested in collaborating None
Currently working on this problem None
This problem looks difficult None
This problem looks tractable None

Additional thanks to: Zach Hunter

When referring to this problem, please use the original sources of Erdős. If you wish to acknowledge this website, the recommended citation format is:

T. F. Bloom, Erdős Problem #1018, https://www.erdosproblems.com/1018, accessed 2026-01-20
PROVED This has been solved in the affirmative.
A planar graph on $n$ vertices with $3n-6$ edges (the maximum possible) is called saturated. Does every graph on $n$ vertices with $\lfloor n^2/4\rfloor+\lfloor \frac{n+1}{2}\rfloor$ edges contain a saturated planar graph with $>3$ vertices?
A saturated planar graph on $3$ vertices is a triangle, which by Turán's theorem is contained in every graph on $n$ vertices with $\lfloor n^2/4\rfloor+1$ edges. Erdős [Er71] writes it is 'easy to construct' a graph on $n$ vertices with $\lfloor n^2/4\rfloor+\lfloor\frac{n-1}{2}\rfloor$ edges which contains no saturated planar graph with $>3$ vertices.

Erdős [Er69c] proved that every graph with $n$ vertices and $\lfloor n^2/4\rfloor+k$ edges contains a saturated planar graph on $\gg k/n$ vertices, answering a question of Dirac.

This was proved in the affirmative by Simonovits in his PhD thesis - indeed, it must contain either a $K_4$ or $C_l+2K_1$ for some $l\geq 3$. The proof is given by Cambie in the comments.

View the LaTeX source

This page was last edited 08 December 2025.

External data from the database - you can help update this
Formalised statement? No (Create a formalisation here)
Likes this problem None
Interested in collaborating None
Currently working on this problem None
This problem looks difficult None
This problem looks tractable None

Additional thanks to: recaje, Stijn Cambie, and Terence Tao

When referring to this problem, please use the original sources of Erdős. If you wish to acknowledge this website, the recommended citation format is:

T. F. Bloom, Erdős Problem #1019, https://www.erdosproblems.com/1019, accessed 2026-01-20
OPEN This is open, and cannot be resolved with a finite computation.
Let $G$ be a graph given by $n$ points in $\mathbb{R}^2$, where any two distinct points are at least distance $1$ apart, and we draw an edge between two points if they are distance $1$ apart.

Let $g(n)$ be maximal such that any such graph always has an independent set on at least $g(n)$ vertices. Estimate $g(n)$, or perhaps $\lim \frac{g(n)}{n}$.
Disclaimer: The open status of this problem reflects the current belief of the owner of this website. There may be literature on this problem that I am unaware of, which may partially or completely solve the stated problem. Please do your own literature search before expending significant effort on solving this problem. If you find any relevant literature not mentioned here, please add this in a comment.
Such graphs are always planar. Erdős initially thought that $g(n)=n/3$, but Chung and Graham, and independently Pach, gave a construction that shows $g(n)\leq \frac{6}{19}n$. Pach and Toth [PaTo96] improved this to $g(n)\leq \frac{5}{16}n$.

Pollack [Po85] noted that the Four colour theorem implies $g(n)\geq n/4$, since the graph is planar. Pollack reports that Pach observed that this in for unit distance graphs the four colour theorem can be proved by a simple induction.

This lower bound has been improved to $\frac{9}{35}n$ by Csizmadia [Cs98] and then $\frac{8}{31}n$ by Swanepoel [Sw02]. The current record bounds are therefore\[\frac{8}{31}n \approx 0.258n \leq g(n) \leq 0.3125n=\frac{5}{16}n.\]Pollack [Po85] also reports a letter from Erdős which poses the more general problem of, given $n$ points in $\mathbb{R}^d$ with minimum distance $1$, let $g_d(n)$ be maximal such that there always exist at least $g_d(n)$ many points which have minimum distance $>1$. Is it true that $g_d(n) \gg n/d$ in general? The upper bound $g_d(n) \ll n/d$ is trivial, considering widely spaced unit simplices.

See [1070] for the general estimate of independence number of unit distance graphs.

View the LaTeX source

This page was last edited 02 October 2025.

External data from the database - you can help update this
Formalised statement? No (Create a formalisation here)
Related OEIS sequences: Possible
Likes this problem None
Interested in collaborating None
Currently working on this problem None
This problem looks difficult None
This problem looks tractable None

When referring to this problem, please use the original sources of Erdős. If you wish to acknowledge this website, the recommended citation format is:

T. F. Bloom, Erdős Problem #1066, https://www.erdosproblems.com/1066, accessed 2026-01-20