OPEN
This is open, and cannot be resolved with a finite computation.
If $n=\prod_{1\leq i\leq t} p_i^{k_i}$ is the factorisation of $n$ into distinct primes then let\[f(n)=\sum p_i^{\ell_i},\]where $\ell_i$ is chosen such that $n\in [p_i^{\ell_i},p_i^{\ell_i+1})$. Furthermore, let\[F(n)=\max \sum_{i=1}^t a_i\]where the maximum is taken over all $a_1,\ldots,a_t\leq n$ such that $(a_i,a_j)=1$ for $i\neq j$ and all prime factors of each $a_i$ are prime factors of $n$.
Is it true that, for almost all $n$,\[f(n)=o(n\log\log n)\]and\[F(n) \gg n\log\log n?\]Is it true that\[\max_{n\leq x}f(n)\sim \frac{x\log x}{\log\log x}?\]Is it true that (for all $x$, or perhaps just for all large $x$)\[\max_{n\leq x}f(n)=\max_{n\leq x}F(n)?\]Find an asymptotic formula for the number of $n<x$ such that $f(n)=F(n)$. Find an asymptotic formula for\[H(x)=\sum_{n<x}\frac{f(n)}{n}.\]Is it true that\[H(x) \ll x\log\log\log\log x?\]
Erdős
[Er84e] proved that\[\max_{n\leq x}f(n)\sim \frac{x\log x}{\log\log x}\]for a sequence of $x\to \infty$.
It is trivial that $f(n)\leq F(n)$ for all $n$. It may be true that, for almost all $n$,\[F(n)\sim \frac{1}{2}n\log\log n.\]Erdős notes that $f(n)/n$ 'almost behaves as a conventional additive function', but unusually $f(n)/n$ does not have a mean value - indeed,\[\limsup \frac{1}{x}\sum_{n<x}\frac{f(n)}{n}=\infty\]but\[\liminf \frac{1}{x}\sum_{n<x}\frac{f(n)}{n}<\infty.\]Erdős
[Er84e] proved that\[x\log\log\log\log x\ll H(x) \ll x\log\log\log x.\]See also
[879].
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T. F. Bloom, Erdős Problem #878, https://www.erdosproblems.com/878, accessed 2026-01-16