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Let $k\geq 3$ and $f_k(N)$ be the maximum value of $\sum_{n\in A}\frac{1}{n}$, where $A$ ranges over all subsets of $\{1,\ldots,N\}$ which contain no subset of size $k$ with the same pairwise least common multiple.

Estimate $f_k(N)$.
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Erdős [Er70] notes that\[f_k(N) \ll \frac{\log N}{\log\log N}.\]Indeed, let $A$ be such a set. This in particular implies that, for every $t$, there are $<k$ solutions to $t=ap$ with $a\in A$ and $p$ prime, whence\[\sum_{n\in A}\frac{1}{n}\sum_{p<N}\frac{1}{p}< k \sum_{t<N^2}\frac{1}{t} \ll \log N,\]and the bound follows since $\sum_{p<N}\frac{1}{p}\gg \log\log N$.

Improved bounds have been given by Tang and Zhang [TaZh25], who proved bounds of the shape\[(\log N)^{b_k-o(1)}\leq f_k(N)\leq (\log N)^{c_k+o(1)}\]for some constants $0<b_k\leq c_k\leq 1$, and in particular\[(\log N)^{0.438}\leq f_3(N)\leq (\log N)^{0.889},\]say, for all large $N$. The exponents here are related to progress in the sunflower conjecture [857], to which this problem is closely related. For example, the exponents $c_k$ are $<1$ (and so the upper bound above is non-trivial) if and only if [857] holds for $k$-sunflowers.

The analogous question with natural density in place of logarithmic density (that is, we measure $\lvert A\rvert$ in place of $\sum_{n\in A}\frac{1}{n}$) is the subject of [536]. In particular Erdős [Er70] has constructed $A\subseteq \{1,\ldots,N\}$ with $\lvert A\rvert \gg N$ where no four have the same pairwise least common multiple, and hence the interest of the natural density problem is the $k=3$ case.

A related combinatorial problem is asked at [857].

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This page was last edited 30 December 2025.

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Additional thanks to: Quanyu Tang

When referring to this problem, please use the original sources of Erdős. If you wish to acknowledge this website, the recommended citation format is:

T. F. Bloom, Erdős Problem #856, https://www.erdosproblems.com/856, accessed 2026-01-16