FALSIFIABLE
Open, but could be disproved with a finite counterexample.
Let $n\geq k+1$. Every graph on $n$ vertices with at least $\frac{k-1}{2}n+1$ edges contains every tree on $k+1$ vertices.
A problem of Erdős and Sós, who also conjectured that every graph with at least\[\max\left( \binom{2k-1}{2}+1, (k-1)n-(k-1)^2+\binom{k-1}{2}+1\right)\]many edges contains every forest with $k$ edges. (Erdős and Gallai
[ErGa59] proved that this is the threshold which guarantees containing $k$ independent edges.)
It can be easily proved by induction that every graph on $n$ vertices with at least $n(k-1)+1$ edges contains every tree on $k+1$ vertices.
Brandt and Dobson
[BrDo96] have proved this for graphs of girth at least $5$. Wang, Li, and Liu
[WLL00] have proved this for graphs whose complements have girth at least $5$. Saclé and Woznik
[SaWo97] have proved this for graphs which contain no cycles of length $4$. Yi and Li
[YiLi04] have proved this for graphs whose complements contain no cycles of length $4$.
Implies
[547] and
[557].
See also
the entry in the graphs problem collection.
View the LaTeX source
This page was last edited 05 October 2025.
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