OPEN
This is open, and cannot be resolved with a finite computation.
Let $h_1(n)=h(n)=n+\tau(n)$ (where $\tau(n)$ counts the number of divisors of $n$) and $h_k(n)=h(h_{k-1}(n))$. Is it true, for any $m,n$, there exist $i$ and $j$ such that $h_i(m)=h_j(n)$?
Asked by Spiro. That is, there is (eventually) only one possible sequence that the iterations of $n\mapsto h(n)$ can settle on. Erdős and Graham believed the answer is yes. Similar questions can be asked by the iterates of many other functions. See also
[412] and
[413].
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This page was last edited 16 November 2025.
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T. F. Bloom, Erdős Problem #414, https://www.erdosproblems.com/414, accessed 2026-01-16