PROVED
This has been solved in the affirmative.
Let $w(n)$ count the number of solutions to\[n=2^a+3^b+2^c3^d\]with $a,b,c,d\geq 0$ integers. Is it true that $w(n)$ is bounded by some absolute constant?
A conjecture originally due to Newman.
This is true, and was proved by Evertse, Györy, Stewart, and Tijdeman
[EGST88].
Quantitative bounds were provided by Tijdeman and Wang
[TiWa88], who proved that (if $w(n)$ only counts distinct solutions, where we call two solutions distinct if the sets $\{2^a,3^b,2^{c}3^d\}$ are distinct) then $w(n) \leq 4$ for all large $n$.
This was made effective by Bajpai and Bennett
[BaBe24], who proved that $w(n)\leq 4$ if $n\geq 131082$ and $w(n)\leq 9$ for all $n$. (The largest $n$ for which $w(n)=9$ is $299$.) There are infinitely many $n$ with $w(n)=4$, given by the identities
\begin{align*}
2^{a-1}+3^b+2^{a-1}3^0
&= 2^{a-2}+3^b+2^{a-2}3^1\\
&=2^a+3^{b-1}+2\cdot 3^{b-1}\\
&=2^a+3^{b-2}+2^33^{b-2}.
\end{align*}
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This page was last edited 18 November 2025.
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