OPEN
This is open, and cannot be resolved with a finite computation.
Let $P(n)$ denote the largest prime factor of $n$. Show that the set of $n$ with $P(n)<P(n+1)$ has density $1/2$.
Conjectured by Erdős and Pomerance
[ErPo78], who proved that this set and its complement both have positive upper density. The best unconditional lower bound available is due to Lü and Wang
[LuWa25], who prove that\[\#\{ n<x :P(n)<P(n+1)\} > (0.2017-o(1))x,\]and the same lower bound for the complement.
In
[Er79e] Erdős also asks whether, for every $\alpha$, the density of the set of $n$ where\[P(n+1)>P(n)n^\alpha\]exists.
Teräväinen
[Te18] has proved that the logarithmic density of the set of $n$ for which $P(n)<P(n+1)$ is $1/2$. Tao and Teräväinen
[TaTe19] have proved that the asymptotic density is $1/2$ at 'almost all scales'.
More generally, for any $0\leq \alpha \leq1$, Teräväinen
[Te18] proved that the logarithmic density of the set of $n$ for which $P(n+1)>P(n)n^\alpha$ exists and is equal to\[\int_{[0,1]^2}1_{y\geq x+\alpha}u(x)u(y)\mathrm{d}x\mathrm{d}y\]where $u(x)=x^{-1}\rho(x^{-1}-1)$ and $\rho$ is the
Dickman function. Wang
[Wa21] has proved the same value holds for the asymptotic density (and in particular provided an affirmative answer to the original question) conditional on the Elliott-Halberstam conjecture for friable integers.
The sequence of such $n$ is
A070089 in the OEIS.
See also
[372] and
[928].
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This page was last edited 08 December 2025.
Additional thanks to: Alfaiz, Agustin Meza, Terence Tao, and Desmond Weisenberg
When referring to this problem, please use the original sources of Erdős. If you wish to acknowledge this website, the recommended citation format is:
T. F. Bloom, Erdős Problem #371, https://www.erdosproblems.com/371, accessed 2026-01-16