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Are there infinitely many solutions to $\phi(n)=\phi(n+1)$, where $\phi$ is the Euler totient function?
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Erdős [Er85e] says that, presumably, for every $k\geq 1$ the equation\[\phi(n)=\phi(n+1)=\cdots=\phi(n+k)\]has infinitely many solutions.

Erdős, Pomerance, and Sárközy [EPS87] proved that the number of $n\leq x$ with $\phi(n)=\phi(n+1)$ is at most\[\frac{x}{\exp((\log x)^{1/3})}.\]See [946] for the analogous question with the divisor function.

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This page was last edited 31 October 2025.

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Related OEIS sequences: A001274
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Additional thanks to: Stijn Cambie

When referring to this problem, please use the original sources of Erdős. If you wish to acknowledge this website, the recommended citation format is:

T. F. Bloom, Erdős Problem #1003, https://www.erdosproblems.com/1003, accessed 2026-01-16