OPEN
This is open, and cannot be resolved with a finite computation.
Are there infinitely many solutions to $\phi(n)=\phi(n+1)$, where $\phi$ is the Euler totient function?
Erdős
[Er85e] says that, presumably, for every $k\geq 1$ the equation\[\phi(n)=\phi(n+1)=\cdots=\phi(n+k)\]has infinitely many solutions.
Erdős, Pomerance, and Sárközy
[EPS87] proved that the number of $n\leq x$ with $\phi(n)=\phi(n+1)$ is at most\[\frac{x}{\exp((\log x)^{1/3})}.\]See
[946] for the analogous question with the divisor function.
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This page was last edited 31 October 2025.
Additional thanks to: Stijn Cambie
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