{"id":338,"date":"2019-04-07T01:32:19","date_gmt":"2019-04-07T09:32:19","guid":{"rendered":"https:\/\/db2tutorial.com\/?page_id=338"},"modified":"2020-04-11T06:59:36","modified_gmt":"2020-04-11T14:59:36","slug":"db2-group-by","status":"publish","type":"page","link":"https:\/\/www.db2tutorial.com\/db2-basics\/db2-group-by\/","title":{"rendered":"Db2 GROUP BY"},"content":{"rendered":"\n<p><strong>Summary<\/strong>: in this tutorial, you will learn how to use the Db2 <code>GROUP BY<\/code> clause to group rows into groups.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">Introduction to Db2 GROUP BY clause<\/h2>\n\n\n\n<p>When you use the <code><a href=\"https:\/\/db2tutorial.com\/db2-basics\/db2-select\/\">SELECT<\/a><\/code> statement to query data, you get a result set which consists of rows. To divide these rows into groups, you use the <code>GROUP BY<\/code> clause as shown in the following query:<\/p>\n\n\n<pre class=\"wp-block-code\" aria-describedby=\"shcb-language-1\" data-shcb-language-name=\"SQL (Structured Query Language)\" data-shcb-language-slug=\"sql\"><span><code class=\"hljs language-sql\"><span class=\"hljs-keyword\">SELECT<\/span>\n    select_list\n<span class=\"hljs-keyword\">FROM<\/span>\n    table_name\n<span class=\"hljs-keyword\">GROUP<\/span> <span class=\"hljs-keyword\">BY<\/span>\n    column1, column2,...;\n<\/code><\/span><small class=\"shcb-language\" id=\"shcb-language-1\"><span class=\"shcb-language__label\">Code language:<\/span> <span class=\"shcb-language__name\">SQL (Structured Query Language)<\/span> <span class=\"shcb-language__paren\">(<\/span><span class=\"shcb-language__slug\">sql<\/span><span class=\"shcb-language__paren\">)<\/span><\/small><\/pre>\n\n\n<p>This statement divides rows derived from the <code>FROM<\/code> clause into groups by one or more column expression (<code>column1<\/code>, <code>column2<\/code>, &#8230;) specified in the <code>GROUP BY<\/code> clause.<\/p>\n\n\n\n<p>When selecting groups of rows from the database, we are interested in the characteristics of the groups, not individual rows. Therefore, we often use <a href=\"https:\/\/db2tutorial.com\/db2-aggregate-functions\/\">aggregate functions<\/a> in conjunction with the <code>GROUP BY<\/code> clause.<\/p>\n\n\n\n<p>An aggregate function takes multiple rows as an input and returns a single value for these rows. Some commonly used aggregate functions are <code><a href=\"https:\/\/db2tutorial.com\/db2-aggregate-functions\/db2-avg\/\">AVG()<\/a><\/code>, <code><a href=\"https:\/\/db2tutorial.com\/db2-aggregate-functions\/db2-count\/\">COUNT()<\/a><\/code>, <code><a href=\"https:\/\/db2tutorial.com\/db2-aggregate-functions\/db2-min\/\">MIN()<\/a><\/code>, <code><a href=\"https:\/\/db2tutorial.com\/db2-aggregate-functions\/db2-max\/\">MAX()<\/a><\/code> and <code><a href=\"https:\/\/db2tutorial.com\/db2-aggregate-functions\/db2-sum\/\">SUM()<\/a><\/code>. For example, the <code>COUNT()<\/code> function returns the number of rows for each group. The <code>AVG()<\/code> function returns the average value of all values in the group.<\/p>\n\n\n\n<p>Here is the common query that uses the <code>GROUP BY<\/code> clause with an aggregate function:<\/p>\n\n\n<pre class=\"wp-block-code\" aria-describedby=\"shcb-language-2\" data-shcb-language-name=\"SQL (Structured Query Language)\" data-shcb-language-slug=\"sql\"><span><code class=\"hljs language-sql\"><span class=\"hljs-keyword\">SELECT<\/span>\n    column1, \n    column2, \n    ...\n    aggregate_function(expression)\n\n<span class=\"hljs-keyword\">FROM<\/span>\n    table_name\n<span class=\"hljs-keyword\">GROUP<\/span> <span class=\"hljs-keyword\">BY<\/span>\n    column1,\n    column2,\n    ...;\n<\/code><\/span><small class=\"shcb-language\" id=\"shcb-language-2\"><span class=\"shcb-language__label\">Code language:<\/span> <span class=\"shcb-language__name\">SQL (Structured Query Language)<\/span> <span class=\"shcb-language__paren\">(<\/span><span class=\"shcb-language__slug\">sql<\/span><span class=\"shcb-language__paren\">)<\/span><\/small><\/pre>\n\n\n<p>Notice that any column listed in the select list that is not in the aggregate function expression must be placed in the <code>GROUP BY<\/code> clause, or you will get an error.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">Db2 GROUP BY clause examples<\/h2>\n\n\n\n<p>Let&#8217;s use the <code>books<\/code> and <code>publishers<\/code> tables from the <a href=\"https:\/\/db2tutorial.com\/getting-started\/db2-sample-database\/\">sample database<\/a> for the demonstration.<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img loading=\"lazy\" decoding=\"async\" width=\"450\" height=\"207\" src=\"https:\/\/db2tutorial.com\/wp-content\/uploads\/2019\/03\/books-and-publishers.png\" alt=\"\" class=\"wp-image-74\" srcset=\"https:\/\/www.db2tutorial.com\/wp-content\/uploads\/2019\/03\/books-and-publishers.png 450w, https:\/\/www.db2tutorial.com\/wp-content\/uploads\/2019\/03\/books-and-publishers-300x138.png 300w\" sizes=\"auto, (max-width: 450px) 100vw, 450px\" \/><\/figure>\n\n\n\n<h3 class=\"wp-block-heading\">1) Using Db2 GROUP BY clause with COUNT(*) function<\/h3>\n\n\n\n<p>This statement uses the <code>GROUP BY<\/code> clause with the <a href=\"https:\/\/db2tutorial.com\/db2-aggregate-functions\/db2-count\/\"><code>COUNT(*)<\/code><\/a> function to find the number of books by publishers:<\/p>\n\n\n<pre class=\"wp-block-code\" aria-describedby=\"shcb-language-3\" data-shcb-language-name=\"SQL (Structured Query Language)\" data-shcb-language-slug=\"sql\"><span><code class=\"hljs language-sql\"><span class=\"hljs-keyword\">SELECT<\/span> \n    publisher_id, \n    <span class=\"hljs-keyword\">COUNT<\/span>(*) book_count\n<span class=\"hljs-keyword\">FROM<\/span> \n    books\n<span class=\"hljs-keyword\">GROUP<\/span> <span class=\"hljs-keyword\">BY<\/span> \n    publisher_id;\n<\/code><\/span><small class=\"shcb-language\" id=\"shcb-language-3\"><span class=\"shcb-language__label\">Code language:<\/span> <span class=\"shcb-language__name\">SQL (Structured Query Language)<\/span> <span class=\"shcb-language__paren\">(<\/span><span class=\"shcb-language__slug\">sql<\/span><span class=\"shcb-language__paren\">)<\/span><\/small><\/pre>\n\n\n<figure class=\"wp-block-image\"><img loading=\"lazy\" decoding=\"async\" width=\"160\" height=\"219\" src=\"https:\/\/db2tutorial.com\/wp-content\/uploads\/2019\/04\/db2-group-by-with-count-function.png\" alt=\"db2 group by with count function\" class=\"wp-image-339\"\/><\/figure>\n\n\n\n<p>In this statement:<\/p>\n\n\n\n<ul class=\"wp-block-list\"><li>The <code>GROUP BY<\/code> clause divides the rows in the books table into groups by the values in the <code>publisher_id<\/code> column.<\/li><li>The <code>COUNT(*)<\/code> returns the number of rows per group.<\/li><\/ul>\n\n\n\n<p>If you want to get the publisher name instead of id, you can join the <code>books<\/code> table to the <code>publishers<\/code> table as shown in the following query:<\/p>\n\n\n<pre class=\"wp-block-code\" aria-describedby=\"shcb-language-4\" data-shcb-language-name=\"SQL (Structured Query Language)\" data-shcb-language-slug=\"sql\"><span><code class=\"hljs language-sql\"><span class=\"hljs-keyword\">SELECT<\/span> \n    p.name  publisher, \n    <span class=\"hljs-keyword\">COUNT<\/span>(*) book_count\n<span class=\"hljs-keyword\">FROM<\/span> \n    books b\n    <span class=\"hljs-keyword\">INNER<\/span> <span class=\"hljs-keyword\">JOIN<\/span> publishers p\n        <span class=\"hljs-keyword\">ON<\/span> p.publisher_id = b.publisher_id\t\n<span class=\"hljs-keyword\">GROUP<\/span> <span class=\"hljs-keyword\">BY<\/span> \n    p.name\n<span class=\"hljs-keyword\">ORDER<\/span> <span class=\"hljs-keyword\">BY<\/span> \n    publisher;   \n<\/code><\/span><small class=\"shcb-language\" id=\"shcb-language-4\"><span class=\"shcb-language__label\">Code language:<\/span> <span class=\"shcb-language__name\">SQL (Structured Query Language)<\/span> <span class=\"shcb-language__paren\">(<\/span><span class=\"shcb-language__slug\">sql<\/span><span class=\"shcb-language__paren\">)<\/span><\/small><\/pre>\n\n\n<p>Here is the output:<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img loading=\"lazy\" decoding=\"async\" width=\"385\" height=\"196\" src=\"https:\/\/db2tutorial.com\/wp-content\/uploads\/2019\/04\/db2-group-by-with-join.png\" alt=\"db2 group by with join\" class=\"wp-image-340\" srcset=\"https:\/\/www.db2tutorial.com\/wp-content\/uploads\/2019\/04\/db2-group-by-with-join.png 385w, https:\/\/www.db2tutorial.com\/wp-content\/uploads\/2019\/04\/db2-group-by-with-join-300x153.png 300w\" sizes=\"auto, (max-width: 385px) 100vw, 385px\" \/><\/figure>\n\n\n\n<h3 class=\"wp-block-heading\">2) Using Db2 GROUP BY clause with AVG() function<\/h3>\n\n\n\n<p>This example uses the <code>GROUP BY<\/code> clause to find the average rating of all books for each publisher.<\/p>\n\n\n<pre class=\"wp-block-code\" aria-describedby=\"shcb-language-5\" data-shcb-language-name=\"SQL (Structured Query Language)\" data-shcb-language-slug=\"sql\"><span><code class=\"hljs language-sql\"><span class=\"hljs-keyword\">SELECT<\/span> \n    publishers.name publisher, \n    <span class=\"hljs-built_in\">DECIMAL<\/span>(<span class=\"hljs-keyword\">AVG<\/span>(rating),<span class=\"hljs-number\">5<\/span>,<span class=\"hljs-number\">2<\/span>) avg_rating,\n    <span class=\"hljs-keyword\">COUNT<\/span>(*) book_count\n<span class=\"hljs-keyword\">FROM<\/span> \n    books\n    <span class=\"hljs-keyword\">INNER<\/span> <span class=\"hljs-keyword\">JOIN<\/span> publishers \n        <span class=\"hljs-keyword\">ON<\/span> publishers.publisher_id = books.publisher_id\t\n<span class=\"hljs-keyword\">GROUP<\/span> <span class=\"hljs-keyword\">BY<\/span> \n    publishers.name\n<span class=\"hljs-keyword\">ORDER<\/span> <span class=\"hljs-keyword\">BY<\/span>\n    publisher;\n<\/code><\/span><small class=\"shcb-language\" id=\"shcb-language-5\"><span class=\"shcb-language__label\">Code language:<\/span> <span class=\"shcb-language__name\">SQL (Structured Query Language)<\/span> <span class=\"shcb-language__paren\">(<\/span><span class=\"shcb-language__slug\">sql<\/span><span class=\"shcb-language__paren\">)<\/span><\/small><\/pre>\n\n\n<figure class=\"wp-block-image\"><img loading=\"lazy\" decoding=\"async\" width=\"453\" height=\"206\" src=\"https:\/\/db2tutorial.com\/wp-content\/uploads\/2019\/04\/db2-group-by-with-avg-function.png\" alt=\"db2 group by with avg function\" class=\"wp-image-341\" srcset=\"https:\/\/www.db2tutorial.com\/wp-content\/uploads\/2019\/04\/db2-group-by-with-avg-function.png 453w, https:\/\/www.db2tutorial.com\/wp-content\/uploads\/2019\/04\/db2-group-by-with-avg-function-300x136.png 300w\" sizes=\"auto, (max-width: 453px) 100vw, 453px\" \/><\/figure>\n\n\n\n<p>In this example:<\/p>\n\n\n\n<ul class=\"wp-block-list\"><li>The <code>GROUP BY<\/code> clause divides the books into groups by the publisher names.<\/li><li>The <code>AVG()<\/code> function returns the average rating of all books for every publisher.<\/li><\/ul>\n\n\n\n<p>Notice that we keep the <code>COUNT(*)<\/code> function in the select list to view the number of books for each publisher.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">3) Using Db2 GROUP BY clause with MIN() and MAX() functions<\/h3>\n\n\n\n<p>The following example finds the minimum &amp; maximum ratings of books for each publisher using the <code><a href=\"https:\/\/db2tutorial.com\/db2-aggregate-functions\/db2-min\/\">MIN()<\/a><\/code> and <code><a href=\"https:\/\/db2tutorial.com\/db2-aggregate-functions\/db2-max\/\">MAX()<\/a><\/code> function with the <code>GROUP BY<\/code> clause:<\/p>\n\n\n<pre class=\"wp-block-code\" aria-describedby=\"shcb-language-6\" data-shcb-language-name=\"SQL (Structured Query Language)\" data-shcb-language-slug=\"sql\"><span><code class=\"hljs language-sql\"><span class=\"hljs-keyword\">SELECT<\/span> \n    publishers.name publisher, \n    <span class=\"hljs-keyword\">MIN<\/span>(rating) min_rating,\n    <span class=\"hljs-keyword\">MAX<\/span>(rating) max_rating\n<span class=\"hljs-keyword\">FROM<\/span> \n    books\n    <span class=\"hljs-keyword\">INNER<\/span> <span class=\"hljs-keyword\">JOIN<\/span> publishers \n        <span class=\"hljs-keyword\">ON<\/span> publishers.publisher_id = books.publisher_id\t\n<span class=\"hljs-keyword\">GROUP<\/span> <span class=\"hljs-keyword\">BY<\/span> \n    publishers.name\n<span class=\"hljs-keyword\">ORDER<\/span> <span class=\"hljs-keyword\">BY<\/span>\n    publisher;\n<\/code><\/span><small class=\"shcb-language\" id=\"shcb-language-6\"><span class=\"shcb-language__label\">Code language:<\/span> <span class=\"shcb-language__name\">SQL (Structured Query Language)<\/span> <span class=\"shcb-language__paren\">(<\/span><span class=\"shcb-language__slug\">sql<\/span><span class=\"shcb-language__paren\">)<\/span><\/small><\/pre>\n\n\n<figure class=\"wp-block-image\"><img loading=\"lazy\" decoding=\"async\" width=\"450\" height=\"220\" src=\"https:\/\/db2tutorial.com\/wp-content\/uploads\/2019\/04\/db2-group-by-with-min-and-max.png\" alt=\"\" class=\"wp-image-342\" srcset=\"https:\/\/www.db2tutorial.com\/wp-content\/uploads\/2019\/04\/db2-group-by-with-min-and-max.png 450w, https:\/\/www.db2tutorial.com\/wp-content\/uploads\/2019\/04\/db2-group-by-with-min-and-max-300x147.png 300w\" sizes=\"auto, (max-width: 450px) 100vw, 450px\" \/><\/figure>\n\n\n\n<h3 class=\"wp-block-heading\">4) Using Db2 GROUP BY clause with SUM() function<\/h3>\n\n\n\n<p>This example uses the <code>GROUP BY<\/code> clause with the <code><a href=\"https:\/\/db2tutorial.com\/db2-aggregate-functions\/db2-sum\/\">SUM()<\/a><\/code> function to find the total pages of all books for each publisher.<\/p>\n\n\n<pre class=\"wp-block-code\" aria-describedby=\"shcb-language-7\" data-shcb-language-name=\"SQL (Structured Query Language)\" data-shcb-language-slug=\"sql\"><span><code class=\"hljs language-sql\"><span class=\"hljs-keyword\">SELECT<\/span> \n    publishers.name publisher, \n    <span class=\"hljs-keyword\">SUM<\/span>(total_pages) total_pages\n<span class=\"hljs-keyword\">FROM<\/span> \n    books\n    <span class=\"hljs-keyword\">INNER<\/span> <span class=\"hljs-keyword\">JOIN<\/span> publishers \n        <span class=\"hljs-keyword\">ON<\/span> publishers.publisher_id = books.publisher_id\t\n<span class=\"hljs-keyword\">GROUP<\/span> <span class=\"hljs-keyword\">BY<\/span> \n    publishers.name;\n<\/code><\/span><small class=\"shcb-language\" id=\"shcb-language-7\"><span class=\"shcb-language__label\">Code language:<\/span> <span class=\"shcb-language__name\">SQL (Structured Query Language)<\/span> <span class=\"shcb-language__paren\">(<\/span><span class=\"shcb-language__slug\">sql<\/span><span class=\"shcb-language__paren\">)<\/span><\/small><\/pre>\n\n\n<figure class=\"wp-block-image\"><img loading=\"lazy\" decoding=\"async\" width=\"385\" height=\"215\" src=\"https:\/\/db2tutorial.com\/wp-content\/uploads\/2019\/04\/db2-group-by-with-sum.png\" alt=\"\" class=\"wp-image-343\" srcset=\"https:\/\/www.db2tutorial.com\/wp-content\/uploads\/2019\/04\/db2-group-by-with-sum.png 385w, https:\/\/www.db2tutorial.com\/wp-content\/uploads\/2019\/04\/db2-group-by-with-sum-300x168.png 300w\" sizes=\"auto, (max-width: 385px) 100vw, 385px\" \/><\/figure>\n\n\n\n<p>In this tutorial, you have learned how to use the Db2 <code>GROUP BY<\/code> clause to divide rows into groups by one or more specified columns.<\/p>\n<div class=\"helpful-block-content\" data-title=\"\">\n\t<header>\n\t\t<div class=\"wth-question\">Was this tutorial helpful ?<\/div>\n\t\t<div 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