ab
A code segment, also known as the text segment holds all the executable instructions of the process. The text segment usually starts from the lowest address space of the process memory (leaving behind a small unmapped memory ..not mapped to a physical memory) --Vivek Purushotham ([email protected])
You can have a function with no parameters.
### posted by Pulkit and Puneet from D.Y.Patil college/pune The ans is NO......... bcoz c compiler already contains the basic functions of STDIO.H in its code segment. ok guys..... ### posted by Pulkit and Puneet from D.Y.Patil college/pune The ans is NO......... bcoz c compiler already contains the basic functions of STDIO.H in its code segment. ok guys.....
Programs that are loaded into memory typically have several segments associated with them: the Code Segment (CS), the Stack Segment (SS), the Data Segment (DS), sometimes an Extended Segment (ES), and almost always a Block Started by Symbol (BSS) segment. This question requires that we focus only on the Code Segment (CS). The CS is a segment of memory that contains some of the instructions that are required for the program to execute. If this segment is not large enough to contain the whole program then the program can be loaded into different segments. Such a segment may be 64Kb in size (although the size may differ). Instructions located in these segments are referred to by their offset from the start of the segment, and not by their absolute location in memory. Thus, in order to locate a certain instruction, we need the segment's starting address, and the offset of the instruction in that segment. Whenever a branch (jump, goto) takes place which refers to an instruction that is located in another segment, it is known as a far jump, conversely whenever a jump refers to an instruction that is located in the same segment, it is known as a near jump. The difference referring to the modication of the CS register which contains the address of the current Code Segment for the current running program.
Code Segment, in which all the application code is stored Data Segment, that holds the global data
Which segment is included by A and C?
Congruent line segment
A+ = segment C A
true
That is correct. The distance from a point C to a line AB is the length of the perpendicular segment drawn from point C to line AB. This forms a right angle, creating a right triangle with the segment as the hypotenuse. The length of this perpendicular segment is the shortest distance from the point to the line.
Yes, the keyword "c" is included in the question.
if segment ab is congruent to segment CD then segment ac is congruent to segment bd (only if points a, b, c, and d are all collinear)
FIN
warmup, strenuous conditioning,and cool down
warmup, strenuous conditioning,and cool down
There are four types of line segments: open, closed and semi open (or semi-closed).With an open line segment, neither end-point is included. In terms of inequalities, it would be of the form a < x < b.Closed segment: both end-points are included so that a ≤ x ≤ b.Semi-open, one end-point is included, the other is not.
a b c and d
False - apex
CD and DC
perpendicular
Assume that the height of the segment is h, the chord length is c and the radius is r then: r2=(r-h)2+(c/2)2 (We join two radii to the two ends of the chord then extend the height of the segment to the center of the circle in which the segment is inscribed so this height will bisect the chord and you use the pythagorean theorem to find the radius)
A line segment, such as segment CD, is a part of a line that connects two distinct endpoints, C and D. It has a definite length, measured as the distance between these two points. In geometry, it is often used to illustrate basic concepts of distance, measurement, and the properties of shapes. The notation for segment CD is typically written as ( \overline{CD} ).
a line segment has only one midpoint "C" but the two sections AC and CE can have their own midpoint "B" and "D" and so on... A B C D E
To create a line segment that's twice as long using a compass and straightedge, first draw the original line segment ( AB ). Next, extend the segment by marking a point ( C ) such that ( AC = AB ) using the compass to measure the length of ( AB ). Finally, draw a line from point ( A ) to point ( C ); the new segment ( AC ) will be twice the length of the original segment ( AB ).
False that is to find the perpendicular bisect.