Function overloading is multiple definition with different signatures(the parameters should be different) for the same function. The parameter list have to be different in each definition. The compiler will not accept if the return type alone is changed.
Operator overloading is defining a function for a particular operator. The operator loading function can not be overloaded through function overloading.
Java does not support opperator overloading, so the answer to your question is: none.
Assignment(=) operator is a special operator that will be provided by the constructor to the class when programmer has not provided(overloaded) as member of the class.(like copy constructor). When programmer is overloading = operator using friend function, two = operations will exists: 1) compiler is providing = operator 2) programmer is providing(overloading) = operator by friend function. Then simply ambiguity will be created and compiler will gives error. Its compilation error.
Overloading, Overriding, Polymorphism, Information Hiding, Inheritance all these are CONCEPTS of C++ and Java. An Object Oriented Language and not of C language. Thats why Bjarne Stroustrup came up with C++ ...
The only similarity is that both constructor and function overloads are distinguished by their signature -- the number and type of their arguments. Functions differ in that they also have a return type, which is also part of the signature, whereas constructors have no return type, not even void.
The prefix increment operator is overloaded as operator++() while the postfix increment operator is overloaded as operator++(int).
No. Operator and/or function overloading is only a C++ thing.
one function but multiple behaviours depending on the parameters
to define an additional task to an operator ,we must specify what it means in relation to the class to which the operator is applied.this is done with the help of a special function called operator function ,which describes the task.
Java does not support opperator overloading, so the answer to your question is: none.
C does not support operator overloading. If you mean C++ operator overloading, it depends on exactly what you wanted to do. If you wanted to '+' to strings, then you could write: string operator+(string a, string b) { // do something }
Assignment(=) operator is a special operator that will be provided by the constructor to the class when programmer has not provided(overloaded) as member of the class.(like copy constructor). When programmer is overloading = operator using friend function, two = operations will exists: 1) compiler is providing = operator 2) programmer is providing(overloading) = operator by friend function. Then simply ambiguity will be created and compiler will gives error. Its compilation error.
operator overloading
Overloading, Overriding, Polymorphism, Information Hiding, Inheritance all these are CONCEPTS of C++ and Java. An Object Oriented Language and not of C language. Thats why Bjarne Stroustrup came up with C++ ...
You cannot create any new operators in C++. You can only overload the existing ones (although some, such as sizeof, new and delete cannot be overloaded). The only way to create a new operator is to implement it as a standard function with a named identifier. For instance, sqrt() is the standard library function that provides the square root operator, for which no real operator exists.
The only similarity is that both constructor and function overloads are distinguished by their signature -- the number and type of their arguments. Functions differ in that they also have a return type, which is also part of the signature, whereas constructors have no return type, not even void.
The prefix increment operator is overloaded as operator++() while the postfix increment operator is overloaded as operator++(int).
It's a way by which you use define the same function for different input types. For example, think about the the operator "+" which in java works for adding integers, floating point numbers and even string concatenation. The way such functionality is achieved is by overloading.
I think you mean operation overlord??? It is the American, Canadian and British offensive on Europe in World War 2. They landed in Normandy on 6th June 1944 (Commonly called D-Day, Day of Days or Deliverance Day) and progressed throughout France liberating Paris on the 25th August. This allowed the allies a foothold in Europe.
Defining several functions with the same name with unique list of parameters is called as function overloading.
The only disadvantage of operator overloading is when it is used non-intuitively. All operators must behave with predictable results, thus it makes no sense to implement the plus (+) operator so that it behaves like a subtract (-) operator, or a multiply (*) operator, or indeed anything other than the intuitive sum of two objects.
in C++ there is no real difference as operators are overloaded by implementing them as functions. However, while we differentiate between function overloads by the function signature (the number and type of parameters), operator overloads are distinguished only by the parameter types. The parameters are interpreted as operands, and the number of operands will depend upon whether the operator is unary, binary or ternary. That is, for any given operator, the number of operands will be the same for each overload you implement. The only exceptions are the unary increment (++) and decrement (--) operators as they each have postfix and prefix variants. In order to differentiate their signatures, an unreferenced or dummy parameter must be passed to the postfix variants.
I will not use operator overloading in C# to do anything. Operator overloading may lead to one operator has more than 1 semantic meaning. For example, we know 1 + 2 yields 3, and "1" + 2 yields "12". I do not like this overloading of the operator + being used for addition in Number hierarchy, while as the concatenation in strings. That is, one operator (+) has 2 significant semantics.And the question "find largest of two object" is too vague - what do you mean "largest"? and object? We know apple and orange are 2 objects, but how do you compare them, and find the largest one?????? (size, price or what???)
Java does not support user defined operator overloading.The operator '+' is overloaded in Java and can be used for adding both numbers and Strings.
The concept of Operator Overloading is similar to Method Overloading, in that the meaning of a given operator symbol changes according to the context it is being used in. That is, the semantics of the operator symbol are flexible, rather than fixed.The idea behind Operator Overloading is to take a common symbol, and adjust it's meaning to something logical for contexts other than what it was originally restricted to.The arithmetic operators ( + - * / ) are good examples. Using Operator Overloading, I could define that 'SomeArray + SomeValue' means that I should add SomeValue to the end of the array SomeArray.In general, Operator Overloading is what is called 'syntactic sugar' - it makes things more readable. For instance, the equivalent way to do the above example via method calls would be: SomeArray.addToEnd(SomeValue)The major problem with Operator Overloading is that it depends on people having the exact same interpretation of what an operator would mean in the new context, which is difficult to assure. Going back to the above example, there is some ambiguity as to where 'SomeArray + SomeValue' would mean to add in SomeValue - should SomeValue be added to the start of the array, or the end of the array? The answer is not obvious, and one would have to go look through the overload definition. While this confusion is also possible with methods, properly named methods (i.e. using addToEnd() rather than just add() ) helps avoid this entirely.For this reason, Java does not support user-defined Operator Overloading. Java does support certain operator overloading in narrow contexts, but only those defined by the language itself. That is, the '+' sign is overloaded to allow for string concatenation. However, the designer of Java (James Gosling) decided that his preference was to avoid Operator Overloading completely due to his perception of a "clean" language.
There is no such thing as function overloading in C; that is a feature of C++. Function overloading allows us to provide two or more implementations of the same function. Typically, we use function overloading so that the same function can cater for different types. For instance, we might provide one implementation that is optimised to handle an integer argument while another is optimised to handle a real argument. We can also use function overloading to provide a common implementation of a function which can then be invoked by overloads that handle the low-level type conversions.