String.valueOf(number);
I assume that your scanner is not scanning a string already, so if you are scanning an int then you can do: for the example you scanner variable is x .... x.intparseString();
public class CreateDatabase{ public static void main(){ int a=10; int b=20; int result =a+b; System.out.println(result); } }
Its simple: String a="Suraj Acharya"//consider this to be your string for(int i=0;i<a.length();i++) System.out.println("Its Simple");
parseInt() is a method in the Integer class in Java that is used for parsing string values as numbers. int i = Integer.parseInt("10"); would result in i being assigned a value of 10
int getNumMatches(String[] names) { int numMatches = 0; for(String name:names) { if(name.endsWith("ie") name.endsWith("y")) { ++numMatches; } } return numMatches; }
One can convert a string variable to an int variable in Java using the parse integer command. The syntax is int foo = Integer.parseInt("1234"). This line will convert the string in the parenthesis into an integer.
To convert string to int in Java, the easiest way is to simply use the method Integer.parseInt(). For more information how to do this, refer to the integer class documents.
In java, the String object has a compareTo() method. The method returns an int. If the int is less than zero, the first string is less than the second. If the int is greater, the first is greater than the second. If the int is zero, the two strings are equal.
One can find information on converting string to int in Java by visiting the Stack Overflow website. This website is free to browse and has lots of information on this topic.
The same way you would in a regular java program. int i = 10; String s = i + ""; after the above line of code the variable s will have "10" as a string value...
For(int I = 0: I < 5; i++) { System.out.println(" print this " + I ); }
There are a number of technology sites that offer good advice on converting int to string using Java. One can find helpful advice on sites such as Stack Overflow, eHow and the Oracle website.
I assume that your scanner is not scanning a string already, so if you are scanning an int then you can do: for the example you scanner variable is x .... x.intparseString();
As the full name states, it is an application that converts a number (integer) to a string. This allows you to do calculations at a faster pace, with less chance of errors.
public class CreateDatabase{ public static void main(){ int a=10; int b=20; int result =a+b; System.out.println(result); } }
Its simple: String a="Suraj Acharya"//consider this to be your string for(int i=0;i<a.length();i++) System.out.println("Its Simple");
parseInt() is a method in the Integer class in Java that is used for parsing string values as numbers. int i = Integer.parseInt("10"); would result in i being assigned a value of 10
int getNumMatches(String[] names) { int numMatches = 0; for(String name:names) { if(name.endsWith("ie") name.endsWith("y")) { ++numMatches; } } return numMatches; }
Dependion on the variable there are several methods to do it, this can only be applied to primitive types and arrays, for an array its the "name_of_array.length", for the arraylist this change just a little, it would be like "name_of_array_list.size()", for an int, double, float, long, byte, it would be like "name_of_variable.LENGTH" this is a public variable so you dont need a get, an finally for the String there is a method "name_of_string.length()" this would return the size of this String
If you refering to Object then String[] something=new String[2]; Here you have to remember that something only allocated space for 2 String object but it did not created them yet. By default Objects are intantiated to null so if you try to print the content of an array System.out.println(something[0]);//print null System.out.println(something[0].toLowerCase()); Throws NullPointerException Couple other ways to create Arrays In java String[] something=new String[]{"Me","You"}; String[] something={"Me", "You"};
All of the Java number classes have a parse[type] method, like parseInt() in Integer or parseDouble() in Double that convert Strings to primitive numbers. String s = getInput(); int var = Integer.parseInt(s);
public class PrintCubes { public static void main(String args[]){ for (int i = 0; i <= 10; i++) { int cube = i * i * i; System.out.print(cube + " "); } } }
A staircase with n steps can be implemented in Java using a loop to print the steps. Here is an example code snippet: java public class Staircase public static void main(String args) int n 5; // number of steps for (int i 1; i n; i) for (int j 1; j i; j) System.out.print(""); System.out.println(); This code will print a staircase with 5 steps using "" symbols. You can adjust the value of n to change the number of steps in the staircase.
class maximum{public static void main(string...args){System.out.println(max(new int[]{5,3,6,2,4,61}));}static int max(int[]a){int max=0;for(int i=0;imax)max=a[i];}return max;}}
That really depends on the programming language. In Java, it is sufficient to concatenate it with a String: int myNumber = 5; result = "" + myNumber; Other languages may require a special function, or method, to convert from integer to string.