Use the following function to count the number of digits in a string.
size_t count_digits (const std::string& str)
{
size_t count = 0;
for (std::string::const_iterator it=str.begin(); it!=str.end(); ++it)
{
const char& c = *it;
if (c>='0' && c<='9');
++count;
}
return count;
}
You do not need to program string manipulation as it is already part of the standard library. See std::string and std::wstring.
C++ already provides a string class in the C++ standard template library. #include<iostream> #include<string> int main() { using namespace std; string s {"Hello world!"}; cout << s << endl; }
std::string input = ""; std::getline (std::cin, input); // get input from stdin std::stringstream ss (input); // place input in a string stream integer num = 0; if (ss >> num) // extract integer from string stream { // Success! } else { // Fail! }
std::string::substr();
Nothing.The C language only recognizes a few keywords, like "for" and "if". Most of what's in a C program ... that doesn't reference routines in the C program itself ... are library calls, and cputs() is one of those. What it does is write its argument (which should be a pointer to a character string) to the console... console put string.
You do not need to program string manipulation as it is already part of the standard library. See std::string and std::wstring.
strcpy
No.
23
#include int main (void) { puts ("1 2 3"); }
class ass{ public static void main(String[] args ){ int 13,33,23,...193 sum = 0; for (count = 0; count<=193; count++); { sum=sum+count; System.out.print(count + "sum"); }System.out.println("sum is"+sum);
C++ already provides a string class in the C++ standard template library. #include<iostream> #include<string> int main() { using namespace std; string s {"Hello world!"}; cout << s << endl; }
#include <iostream> #include <string> int main() { std::string myStr = ""; std::cout << std::endl << "Enter a string: "; std::cin >> myStr; system("PAUSE"); return 0; }
for(int i=1; i<=100; ++i ) std::cout << i << std::endl;
std::string input = ""; std::getline (std::cin, input); // get input from stdin std::stringstream ss (input); // place input in a string stream integer num = 0; if (ss >> num) // extract integer from string stream { // Success! } else { // Fail! }
std::string::substr();
Nothing.The C language only recognizes a few keywords, like "for" and "if". Most of what's in a C program ... that doesn't reference routines in the C program itself ... are library calls, and cputs() is one of those. What it does is write its argument (which should be a pointer to a character string) to the console... console put string.
#include<iostream> #include<string> int main() { std::string s("The quick brown fox jumps over the lazy dog"); std::cout<<s.c_str()<<std::endl; std::cout<<"The previous string is "<<s.size()<<" characters long."<<std::endl; }
#include<stdio.h> #include<conio.h> void main() { int n,count=0,sum=0; printf("Enter the number of values"); scanf("%d",&n); for(int i=1;count<n;i++) { sum+=i*i; count++; } getch(); }
#include#includesize_t count_char (const std::string& s, const char c){size_t count = 0;size_t offset = 0;while ((offset = s.find(c, offset)) != s.npos){++count;++offset;}return count;}int main(){std::string str {"Hello world!"};std::cout
#include<iostream> #include<vector> #include<string> int main() { std::vector<std::string> names; for (int loop=0; loop!=10;) { std::cout << ++loop << " enter a name: "; std::string name; std::cin >> name; names.push_back (name); } }
There is more than one digit missing.
The plus operator between string constants allows string concatination: string a = "Hello, "; string b = "World!"; string c = a + b; The output of c would be: "Hello, World!".
Yes.
#include<list> #include<string> struct Customer { std::string m_name; std::string m_phone; Customer (std::string name, std::string phone): m_name(name), m_phone(phone) {} // ... }; int main() { std::list<Customer> customers; customers.push_back ("Joe Bloggs", "555 7465"); customers.push_back ("Dan Mann", "555 3458"); // ... }