Exactly what do you mean by 'C program in Java'
#include #include void main(void) { int i,j,k,n; clrscr(); i=0; j=1; printf("%d %d ",i,j); for(n=0;n<=5;n++) { k=i+j; i=j; j=k; printf("%d ",k); } getch(); }
i dn't know. haha
//to generate Fibonacci series upto a range of 200....(in C).... #include<stdio.h> main() { int a,b,c,i; a=0; b=1; printf("\n FIBONACCI SERIES .....\t"); i=1; while(i<=(200-2)) { c=a+b; printf("\t%d",c); a=b; b=c; i++; } }
#include<iostream> unsigned fib (unsigned term, unsigned a=0, unsigned b=1) { if (term<1) return a; return fib (--term, a+b, a); } int main() { std::cout << "Fibonacci (1000th term): " << fib (1000) << std::endl; }
//WAP to print fibonacci series using do-while loop.? using System; class Fibonacci { public static void Main() { int a=1,b=1; int sum=0; Console.Write("Enter Limit:"); int n=Int32.Parse(Console.ReadLine()); Console.Write(a); Console.Write(b); do { sum=a+b; a=b; b=sum; Console.Write(sum); } while(sum<n); } } By-Vivek Kumar Keshari
You can write a C++ fib pro using arrays but the problem is the prog becomes very complicated since u need to pass the next adding value in an array.....
#include#includevoid fibonacci(int x){int f=0,m=-1,n=1,i=0;while(i
HTML has no notion of a loop. This cannot be done.
#include<stdio.h> #include<conio.h> void fibonacci(int x) { int f=0,m=-1,n=1,i; for(i=0;i<x;i++) { f=m+n; printf("%d\n",f); m=n; n=f; } } void main() { int n; clrscr(); printf("\nEnter the limit:"); scanf("%d",&n); fibonacci(n); getch(); }
1.34472 x 1099 (rounded to 6 sig. figures) You can figure this out using simple formulas in a spreadsheet program such as Excel. 1070066266382758936764980584457396885083683896632151665013235203375314520604694040621889147582489792657804694888177591957484336466672569959512996030461262748092482186144069433051234774442750273781753087579391666192149259186759553966422837148943113074699503439547001985432609723067290192870526447243726117715821825548491120525013201478612965931381792235559657452039506137551467837543229119602129934048260706175397706847068202895486902666185435124521900369480641357447470911707619766945691070098024393439617474103736912503231365532164773697023167755051595173518460579954919410967778373229665796581646513903488154256310184224190259846088000110186255550245493937113651657039447629584714548523425950428582425306083544435428212611008992863795048006894330309773217834864543113205765659868456288616808718693835297350643986297640660000723562917905207051164077614812491885830945940566688339109350944456576357666151619317753792891661581327159616877487983821820492520348473874384736771934512787029218636250627816
to print the Fibonacci series until 100 you can take the input in d to make it run for whatever value you want void main(){ int a,b,c,d; a=0; b=1; c=1; d=100; while(c<d) { printf("%d\n",c); c=a+b; a=b; b=c; } }
The Fibonacci sequence uses recursion to derive answers. It is defined as: F0 = 0 F1 = 1 Fn = F(n - 1) + F(n -2) To have this sequence printed by a php script use the following: function fibonacci($n) { if($n 1) return 1; //F1 else return fibonacci($n - 1) + fibonacci($n - 2); //Fn } This recursive function will print out the Fibonacci number for the integer n. To make it print out all the numbers in a particular set add this to your script. for($i = 0; $i < 15; $i++) { echo fibonacci($i) . "<br />"; } So your final result would look like. <?php function fibonacci($n) { if($n 1) return 1; else return fibonacci($n - 1) + fibonacci($n - 2); } for($i = 0; $i < 15; $i++) { echo fibonacci($i) . "<br />"; } ?>
Here is a good answer for recursion Fibonacci series. #include <stdio.h> #include <conio.h> long Fibonacci(long n); int main() { long r, n,i; printf("Enter the value of n: "); scanf("%ld",&n); for(i=0;i<=n;i++) { printf(" Fibonacci(%ld)= %ld\n", i,Fibonacci(i)); } getch(); return 0; } long Fibonacci(long n) { if(n==0 n==1) return n; else { return (Fibonacci(n-1)+Fibonacci(n-2)); } } for n=5; Output: Fibonacci(0)=0 Fibonacci(1)=1 Fibonacci(2)=1 Fibonacci(3)=2 Fibonacci(4)=3 Fibonacci(5)=5
#include <iostream> using std::cout; using std::endl; int main() { int i = 0; int j = 1; int k; cout << i << ' ' << j << ' '; while (i + j <= 10000) { k = i + j; cout << k << ' '; i = j; j = k; } cout << endl; return 0; }
In c: int fibr(int n) { // Find nth Fibonacci number using recursion. if (n<=2) return 1; // the first two Fibonacci numbers are 1 and 1 return (fibr(n-2)+fibr(n-1)); } int fibi(int n) { // Find nth Fibonacci number using iteration. int temp,last=1,f=1; int i; for (i=3;i<n;++i) { // the first two Fibonacci numbers are 1 and 1 temp=f; f+=last; last=temp; } return f; }
write a sample program using asp.net explaining all the syntax and semantics of the program
The Fibonacci series in assembly language involves generating a sequence where each number is the sum of the two preceding ones, typically starting with 0 and 1. In assembly, this can be implemented using loops and registers to store the current and previous Fibonacci numbers. The program iteratively calculates the next number in the series until a specified limit is reached. The exact implementation can vary depending on the specific assembly language syntax and architecture, such as x86 or ARM.
write a vb program to find the magic square
class Fibonacci { public static void main(String args[]) { System.out.println("enter the number upto u want"); int number=Integer.parseInt(args[0]); int a=0,b=1,c=0; System.out.print(a+" "+b); for(int i=1;i<=number;i++) { c=a+b; System.out.print(c+" "); a=b; b=c; } } } the number are given to the run time where are print the series eg: 5 0 1 1 2 3 5 8 13................
Write and run a client and a server program in C-language using UDP