C does not support operator overloading.
If you mean C++ operator overloading, it depends on exactly what you wanted to do. If you wanted to '+' to strings, then you could write:
string operator+(string a, string b) {
// do something
}
No. Operator and/or function overloading is only a C++ thing.
one function but multiple behaviours depending on the parameters
You cannot overload operators in C. This is a C++ thing only.
Java does not support opperator overloading, so the answer to your question is: none.
Overloading, Overriding, Polymorphism, Information Hiding, Inheritance all these are CONCEPTS of C++ and Java. An Object Oriented Language and not of C language. Thats why Bjarne Stroustrup came up with C++ ...
one reason to use new and delete operator overloading in c++ is when you are using your own memory manager code. when the user of your code calls the new keywork, your memory manager code can allocate memory.
I will not use operator overloading in C# to do anything. Operator overloading may lead to one operator has more than 1 semantic meaning. For example, we know 1 + 2 yields 3, and "1" + 2 yields "12". I do not like this overloading of the operator + being used for addition in Number hierarchy, while as the concatenation in strings. That is, one operator (+) has 2 significant semantics.And the question "find largest of two object" is too vague - what do you mean "largest"? and object? We know apple and orange are 2 objects, but how do you compare them, and find the largest one?????? (size, price or what???)
A C operator is not a job or profession but rather a coding language. C operators perform certain tasks in programming such as a "+ " operator performs addition.
I think you mean operation overlord??? It is the American, Canadian and British offensive on Europe in World War 2. They landed in Normandy on 6th June 1944 (Commonly called D-Day, Day of Days or Deliverance Day) and progressed throughout France liberating Paris on the 25th August. This allowed the allies a foothold in Europe.
operator overloading
Operator overloading allows c/c++ operators to have user defined meanings on user defined types. For example + operator is used to add to numbers but we can also use it for concatenating a string the only limitation is you cannot change the literal meaning of the operator.
Function overloading is multiple definition with different signatures(the parameters should be different) for the same function. The parameter list have to be different in each definition. The compiler will not accept if the return type alone is changed. Operator overloading is defining a function for a particular operator. The operator loading function can not be overloaded through function overloading.
You cannot create a new operator through operator overloading. You can only redefine an existing operator, with certain limitations. As an example, for a class of complex numbers, having a real and an imaginary part, you might want an addition operator. This is the skeleton of code to do that. I only show the operator, not any constructors or other operators or methods, etc.class complex {private:double real, imaginary;public:complex operator+ (complex operand) {complex temp;temp.real = this.real + operand.real;temp.imaginary = this.imaginary + operand.imaginary;return temp;}};The above answer is for C++. Since this question is also categorized in Java Programming it's important to note that operator overloading is not currently possible in Java.
== == === === === === === === Some Body told me that operator overloading is not there because it violates the transparency of java.since there is no hiding of information in java it does support op overloading === === === === === === Pranab Kumar Rana Software Engineer..... === === === ===
The prefix increment operator is overloaded as operator++() while the postfix increment operator is overloaded as operator++(int).
The only disadvantage of operator overloading is when it is used non-intuitively. All operators must behave with predictable results, thus it makes no sense to implement the plus (+) operator so that it behaves like a subtract (-) operator, or a multiply (*) operator, or indeed anything other than the intuitive sum of two objects.
Java does not support user defined operator overloading.The operator '+' is overloaded in Java and can be used for adding both numbers and Strings.
Maybe because Sun said so. We have to bear with so many other idiosyncrasies too. But I guess that comes with every language. There were two major reasons why operator overloading wasn't allowed in Java: "cleanliness" and compiler complexity. The main reason was the first, a personal preference choice made by Java's creator, James Gosling. Operator overloading, while useful, can be exceedingly confusing, much more so than method overloading. Given the human tendency to assign specific meanings to single symbols, it is hard to get programmers to wrap their heads around multiple meanings for operators. What this means is that there is a marked increase in programming errors when a language supports operator overloading. Since practically the same benefit can be obtained via methods, the Java designers decided that the increased programmer mistake rate was not worth supporting operator overloading. From a Java compiler (e.g. javac) design standpoint, supporting operator overloading is considerably more difficult than method overloading, requiring a more complex compiler.
You cannot create any new operators in C++. You can only overload the existing ones (although some, such as sizeof, new and delete cannot be overloaded). The only way to create a new operator is to implement it as a standard function with a named identifier. For instance, sqrt() is the standard library function that provides the square root operator, for which no real operator exists.
There are 5 operators which cannot be overloaded. They are: * .* - class member access operator * :: - scope resolution operator * . - dot operator * ?:: - conditional operator * Sizeof() - operator Note:- This is possible only in C++.