Academia.edu no longer supports Internet Explorer.
To browse Academia.edu and the wider internet faster and more securely, please take a few seconds to upgrade your browser.
Proceedings - Mathematical Sciences
In this paper, we solve the simultaneous Diophantine equations (SDE) x µ 1 + x µ 2 + • • • + x µ n = k • (y µ 1 + y µ 2 + • • • + y µ n k), µ = 1, 3, where n ≥ 3, and k = n, is a divisor of n (n k ≥ 2), and obtain nontrivial parametric solution for them. Furthermore we present a method for producing another solution for the above Diophantine equation (DE) for the case µ = 3, when a solution is given. We work out some examples and find nontrivial parametric solutions for each case in nonzero integers. Also we prove that the other DE n i=1 p i • x ai i = m j=1 q j • y bj j , has parametric solution and infinitely many solutions in nonzero integers with the condition that: there is a i such that p i = 1, and (a i , a 1 • a 2 • • • a i−1 • a i+1 • • • a n • b 1 • b 2 • • • b m) = 1, or there is a j such that q j = 1, and (b j , a 1 • • • a n • b 1 • • • b j−1 • b j+1 • • • b m) = 1. Finally we study the DE x a + y b = z c .
arXiv: Number Theory, 2017
In this paper, we solve the simultaneous Diophantine equations m.(x_1^k+....+x_{t_1}^k)=n.(y_1^k+....+y_{t_2}^k); k=1,3, where t_1, t_2>3, and m, n are fixed arbitrary and relatively prime positive integers. This is done by choosing two appropriate trivial parametric solutions and obtaining infinitely many nontrivial parametric solutions. Also we work out some examples, in particular the Diophantine systems of A^k+B^k+C^k=D^k+E^4; k=1,3.
Proceedings - Mathematical Sciences, 2011
proved that a product of consecutive integers can never be a perfect power. That is, the equation x(x + 1)(x + 2)...(x + (m − 1)) = y n has no solutions in positive integers x, m, n where m, n > 1 and y ∈ Q. We consider the equation where 0 ≤ a 1 < a 2 < · · · < a k are integers and, with r ∈ Q, n ≥ 3 and we prove a finiteness theorem for the number of solutions x in Z, y in Q. Following that, we show that, more interestingly, for every nonzero integer n > 2 and for any nonzero integer r which is not a perfect n-th power for which the equation admits solutions, k is bounded by an effective bound.
Journal of Number Theory, 2014
In this note we consider Diophantine equations of the form
2014
This paper was first published in www.arxiv.org, on July 17, 2013. (See arXiv: 1307.5328(math.NT)). This typewritten paper is 19 pages long. In this work we accomplish three goals. First, we determine the entire family of solutions to the 3-variable Diophantine equation xy= z^n, for n=2,3,4,5,6. For n=2, a 3-parameter family of solutions. For n=3 and n=4; a 5-parameter family of solutions. For n=5 and n=6, a 7-parameter family of solutions. See Theorems2 through 6, respectively. The second goal of this paper, is determining all the positive integer solutions of the equation xyz= w^2. This is done in Th.7, the solution set is described in terms of six independent parameters. Finally, in Theorem8, we achieve our third goal: namely, we determine all the positive integer solutions of the 5-variable Diophantine system, xy=v^2 and yz= w^2. The solution set to this system, is described in terms of eight parameters. This paper contains four references.
Let í µí± ≔ í µí±(í µí±¡) be a polynomial in í µí² í µí±¥. In this paper, we consider the polynomial solutions of Diophantine equation í µí°·: í µí°¾ 2 − 56í µí± 2 − 32í µí°¾ − 224í µí± − 224 = 0. We also obtain some formulae and recurrence relations on the polynomial solution (í µí°¾ í µí± , í µí± í µí±) of í µí°·. 1. Introduction A Diophantine equation is a polynomial equation í µí± í µí±¥ 1 , í µí±¥ 2 , ⋯ , í µí±¥ í µí± = 0 where the polynomial í µí± has integral coefficients and one is interested in solutions for which all the unknowns take integer values. For example, í µí±¥ 2 + í µí±¦ 2 = í µí± § 2 and í µí±¥ = 3, í µí±¦ = 4, í µí± § = 5 is one of its infinitely many solutions. Another example is í µí±¥ + í µí±¦ = 1 and all its solutions are given by í µí±¥ = í µí±¡, í µí±¦ = 1 − í µí±¡ where í µí±¡ passes through all integers. A third example is í µí±¥ 2 + 4í µí±¦ = 3. This Diophantine equation has no solutions, although note that í µí±¥ = 0, í µí±¦ =
Proceedings - Mathematical Sciences, 2018
In this study, the diophantine equations x 2 − 32B n x y − 32y 2 = ±32 r , x 4 − 32B n x y − 32y 2 = ±32 r and x 2 − 32B n x y − 32y 4 = ±32 r are considered and determined when these equations have positive integer solutions. Moreover, all positive integer solutions of these diophantine equations in terms of balancing and Lucasbalancing numbers are also found out.
Journal of Number Theory, 2014
This note presents corrections to the paper by Y. Wang and T. Wang [2]. The unique theorem given in that paper states that for any odd integer n > 1, nx 2 + 2 2m = y n has no positive integer solution (x, y, m) with gcd(x, y) = 1.
In this note we present a method of solving this Diophantine equation, method which is different from Ljunggren’s, Mordell’s, and R.K.Guy’s.
2021
In this paper, by using elliptic curves theory, we study the quartic Diophantine equation (DE) ∑n i=1 aix 4 i = ∑n j=1 ajy 4 j , where ai and n ≥ 3 are fixed arbitrary integers. We try to transform this quartic to a cubic elliptic curve of positive rank. We solve the equation for some values of ai and n = 3, 4, and find infinitely many nontrivial solutions for each case in natural numbers, and show among other things, how some numbers can be written as sums of three, four, or more biquadrates in two different ways. While our method can be used for solving the equation for n ≥ 3, this paper will be restricted to the examples where n = 3, 4. Finally, we explain how to solve more general cases (n ≥ 4) without giving concrete examples to case n ≥ 5.
Mathematics and Statistics
Numerous researches have been devoted in finding the solutions (, ,), in the set of non-negative integers, of Diophantine equations of type + = 2 (1), where the values and are fixed. In this paper, we also deal with a more generalized form, that is, equations of type + = 2 (2), where is a positive integer. We will present results that will guarantee the non-existence of solutions of such Diophantine equations in the set of positive integers. We will use the concepts of the Legendre symbol and Jacobi symbol, which were also used in the study of other types of Diophantine equations. Here, we assume that one of the exponents is odd. With these results, the problem of solving Diophantine equations of this type will become relatively easier as compared to the previous works of several authors. Moreover, we can extend the results by considering the Diophantine equations + 1 1 2 2 … = 2 (3) in the set of positive integers.
Journal of Number Theory, 2011
The title equation, where p > 3 is a prime number ≡ 7 (mod 8), q is an odd prime number and x, y, n are positive integers with x, y relatively prime, is studied. When p ≡ 3 (mod 8), we prove (Theorem 2.3) that there are no solutions. For p ≡ 3 (mod 8) the treatment of the equation turns out to be a difficult task. We focus our attention to p = 5, by reason of an article by F.
We know already that the set of positive integers, which are satisfying the Pythagoras equation of three variables and four variables are called Pythagorean triples & quadruples respectively. These are Diophantine equation of second power. The all unknowns in this Pythagorean equation have already been solved by mathematicians Euclid & Diophantine. However the solution defined by Euclid & Diophantine is also again having unknowns. The only possible to solve the Diophantine equations was trial & error method. Moreover, the trial & error method to obtain these values are not so practical and easy especially for time bound works, since the Diophantine equations are having more than two unknown variables. The scope of work is to solve the (1) Pythagorean triples1, (2) Pythagorean Quadruples2 & n-tuples and (3) Diophantine equations of third & fourth power3 by simple method. After conducting various exercises, the author has realized that there is a mathematical relation in between the variables and he has attempted to establish the necessary formulae to solve these equations. These formulae & methods have been proved with appropriate examples. It is very useful for Students, Research scholars and persons those who are preparing question papers related to right-angled triangles, rectangular prisms and Number theory4.
Journal of Number Theory, 2016
In this paper we investaigate Diophantine equations of the form T 2 = G(X), X = (X 1 ,. .. , Xm), where mainly m = 3 or m = 4 and G specific homogenous quintic form. First, we prove that if F (x, y, z) = x 2 + y 2 + az 2 + bxy + cyz + dxz ∈ Z[x, y, z] and (b − 2, 4a − d 2 , d) = (0, 0, 0), then the Diophantine equation t 2 = nxyzF (x, y, z) has solution in polynomials x, y, z, t with integer coefficients, without polynomial common factor of positive degree. In case a = d = 0, b = 2 we prove that there are infinitely many primitive integer solutions of the Diophantine equation under consideration. As an application of our result we prove that for each n ∈ Q \ {0} the Diophantine equation 2010 Mathematics Subject Classification. 11D41.
2001
Among other things we show that for each n-tuple of positive rational numbers (a 1 ; : : : ; a n ) there are sets of primes S of arbitrarily large cardinality s such that the solutions of the equation a 1 x 1 + +a n x n = 1 with x 1 ; : : : ; x n S-units are not contained in fewer than exp((4 + o(1))s 1=2 (log s) 1=2 ) proper linear subspaces of C n . This generalizes a result of Erdős, Stewart and Tijdeman [7] for S-unit equations in two variables. Further, we prove that for any algebraic number field K of degree n, any integer m with 1 m < n, and any sufficiently large s there are integers 0 ; : : : ; m in K which are linearly independent over Q , and prime numbers p 1 ; : : : ; p s , such that the norm polynomial equation jN K=Q ( 0 + 1 x 1 + + mxm )j = p z1 1 p zs s has at least expf(1+o(1)) n m s m=n (log s) 1+m=n g solutions in x 1 ; : : : ; xm ; z 1 ; : : : ; z s 2 Z. This generalizes a result of Moree and Stewart [19] for m = 1. Our main tool, also established in this pap...
Journal of Number Theory, 2005
Let D > 2 be a positive integer, and let p be an odd prime not dividing D. In this paper, using the deep result of Bilu, Hanrot and Voutier (i.e., the existence of primitive prime factors of Lucas and Lehmer sequences), by computing Jacobi's symbols and using elementary arguments, we prove that: if (D, p) = (4, 5), (2, 5), then the diophantine equation x 2 + D m = p n has at most two positive integer solutions (x, m, n). Moreover, both x 2 + 4 m = 5 n and x 2 + 2 m = 5 n have exactly three positive integer solutions (x, m, n).
JP Journal of Algebra, Number Theory and Applications
2014
It is shown that infinitely many primitive solutions on the Diophantine equations of the title can be found on employing the theory of elliptic curves, which makes it possible to naturally find larger solutions in a matter of minutes.
Communications in Mathematics and Applications
In this paper, we study on the exponential Diophantine equations: n x + 24 y = z 2 , for n ≡ 5 or 7 (mod 8). We show that 5 x + 24 y = z 2 has a unique positive integral solution (2, 1, 7). Further, we show that for k ∈ N, (8k + 5) x + 24 y = z 2 has a unique solution (0, 1, 5) in non-negative integers. We also show that for a perfect square 8m, the exponential Diophantine equation (8m − 1) x + 24 y = z 2 , m ∈ N has exactly two non-negative integral solutions (0, 1, 5) and (1, 0, 8m). Otherwise, it has a unique solution (0, 1, 5). Finally, we illustrate our results with some examples and non-examples.
South East Asian J. of Mathematics and Mathematical Sciences
In this note, we show that for n = 4N + 3, N N 0 , the expo- nential Diophantine equation nx + 24y = z2 has exactly two solutions if n + 1 or equivalently N + 1 is an square. When N + 1 = m2, the solutions are given by (0, 1, 5) and (1, 0, 2m). Otherwise it has a unique solution (0, 1, 5) in non-negative integers. Finally, we leave an open problem to explore.
Loading Preview
Sorry, preview is currently unavailable. You can download the paper by clicking the button above.