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Rings over which all modules are I 0-modules. II

2009, Journal of Mathematical Sciences

Abstract

All right R-modules are I0-modules if and only if either R is a right SV-ring or R/I (2) (R) is an Artinian serial ring such that the square of the Jacobson radical of R/I (2) (R) is equal to zero. All rings are assumed to be associative and with nonzero identity element. Expressions such as "an Artinian ring" mean that the corresponding right and left conditions hold. A submodule X of the module M is said to be superfluous in M if X + Y = M for every proper submodule P of the module M. Following [9], we call a module M an I 0-module if every nonsuperfluous submodule of M contains a nonzero direct summand of the module M. It is clear that I 0-modules are weakly regular modules, considered in [1-3, 8]; a module M is said to be weakly regular if every submodule of M that is not contained in the Jacobson radical of M contains a nonzero direct summand of M. Weakly regular modules are studied in [1-3; 6; 8; 9; 11, Chap. 3; 12-14], and other papers. A ring R is called a right generalized SV-ring if every right R-module is weakly regular. It is clear that A is a right generalized SV-ring provided each right A-module is an I 0-module. In addition, it follows from the presented paper that the Jacobson radical of any right module over a right generalized SV-ring is superfluous; therefore, every right module over a right generalized SV-ring is an I 0-module. The aim of the paper is the study of generalized right SV-rings. The main result of the present paper is Theorem 1.

Key takeaways

  • For a ring R, the following conditions are equivalent.
  • If M is a module, then any module that is isomorphic to a submodule of some homomorphic image of a direct sum of copies of M is called an M -subgenerated module.
  • Further, we denote by I (2) (R) the right ideal I (1) If MI (2) (R) = 0, then M contains a nonzero local injective submodule of length at most 2.
  • Then N contains a local submodule of length 2 that is an injective R-module.
  • Since every S-module is weakly regular, it follows from Lemma 6 that S S contains a nonzero injective submodule of the form eS, where e is some idempotent of the ring S. Since the ring eSe is isomorphic to the endomorphism ring of the injective module eS and J(eSe) = 0, it follows from [17, 22.1] that eSe is a regular right self-injective ring.