Papers by SALVADOR ANTONIO RADA ESCOBAR
CHAPTER 2 ATOMIC STRUCTURE AND INTERATOMIC BONDING PROBLEM SOLUTIONS 2.1 (a) When two or more ato... more CHAPTER 2 ATOMIC STRUCTURE AND INTERATOMIC BONDING PROBLEM SOLUTIONS 2.1 (a) When two or more atoms of an element have different atomic masses, each is termed an isotope. (b) The atomic weights of the elements ordinarily are not integers because: (1) the atomic masses of the atoms generally are not integers (except for 12 C), and (2) the atomic weight is taken as the weighted average of the atomic masses of an atom's naturally occurring isotopes. 2.2 Atomic mass is the mass of an individual atom, whereas atomic weight is the average (weighted) of the atomic masses of an atom's naturally occurring isotopes. 2.3 (a) In order to determine the number of grams in one amu of material, appropriate manipulation of the amu/atom, g/mol, and atom/mol relationships is all that is necessary, as # g/amu = 1 mol 6.023 x 10 23 atoms 3 2 = 6.62 x 10-29 m 3 3.4 This problem calls for a demonstration of the relationship a = 4R 3 for BCC. Consider the BCC unit cell shown below Using the triangle NOP [AtomProps] Gold=LtRed,0.14 Copper=LtYellow,0.13
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Papers by SALVADOR ANTONIO RADA ESCOBAR