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A parallelepiped is a three-dimensional solid shape that looks like a box with six sides, where each side is a parallelogram. It is a type of prism with a parallelogram as its base. Three-dimensional shapes, or 3D shapes, have length, width, and height, which are used to measure them. In this topic, we will learn about the parallelepiped, its key properties, and the formulas to find its total surface area, lateral surface area, and volume. We will also look at the equation for a rectangular parallelepiped and solve examples to understand how to apply these formulas in real problems.
A parallelepiped is a three-dimensional figure formed by six parallelograms and it can be defined as a polyhedron with six faces also called a hexahedron with each face a parallelogram. A parallelepiped is also called a rhomboid. By analogy with 2D Shapes, it correlates to a parallelogram just as a cube relates to a square. The rectangular cuboid having six rectangular faces, a cube having six square faces, and the rhombohedron with six rhombus faces are all specific cases of the parallelepiped.
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The volume of the parallelepiped is the amount of space a parallelepiped contains. To understand this consider a parallelepiped filled with water. The volume of water that fits in the parallelepiped is the volume of the parallelepiped.
The volume of the parallelepiped is the area of the base times the height. From the geometric definition of the cross product, we know that its magnitude, ∥a×b∥, is the area of the parallelogram base, and that the direction of the vector a×b is perpendicular to the base. To describe a parallelepiped, we need its three adjacent sides and the measure of the angles between them, or the three adjacent vectors.

Volume of Parallelepiped Formula: Formula for the volume of a parallelepiped formed by vectors \(\vec{a}\), \(\vec{b}\) and \(\vec{c}\) with the same initial point is given by their scalar triple product:
\(V=∣(\vec{a}\times\vec{b})\cdot\vec{c}∣\).
V – Volume of the parallelepiped formed by the three vectors; \(\vec{a}\), \(\vec{b}\) and \(\vec{c}\)
The first step of calculating the volume of the parallelepiped involves finding the cross product or vector product of \((\vec{a}\times\vec{b})\). The product vector is perpendicular to both \(\vec{a}\) and \(\vec{b}\). Note that the magnitude of the resultant vector, \(\lvert\vec{a}\times\vec{b}\rvert\), is equal to the area of a parallelogram described by these two vectors.
The subsequent dot product between \((\vec{a}\times\vec{b})\) and \(\vec{c}\) denotes the projection of \(\vec{a}\times\vec{b}\) on \(\vec{c}\). In other words, it sweeps the base parallelogram along \(\vec{c}\), analogous to multiplying the base area with height.
We can further simplify the formula and reduce it to one determinant:
\(\begin{matrix}
(\vec{a}\times\vec{b})\cdot\vec{c}
&=
\left|
\begin{array}{cc}
a_2 & a_3\\
b_2 & b_3
\end{array}
\right|
c_1
–
\left|
\begin{array}{cc}
a_1 & a_3\\
b_1 & b_3
\end{array}
\right|
c_2
+
\left|
\begin{array}{cc}
a_1 & a_2\\
b_1 & b_2
\end{array}
\right|
c_3
\\
&=
\left|
\begin{array}{ccc}
c_1 & c_2 & c_3\\
a_1 & a_2 & a_3\\
b_1 & b_2 & b_3
\end{array}
\right|.
\end{matrix}\)
This gives us the volume of the parallelepiped when the vectors \(\vec{a}\), \(\vec{b}\) and \(\vec{c}\) are known.
If we know the vertices of a parallelepiped we can find out its vectors by using the simple distance formula. If \(A < x_1, y_1, z_ 1 >, B < x_2, y_2, z_ 2 >\), \(C < x_3, y_3, z_ 3 >\) and \(D < x_4, y_4, z_ 4 >\) then we can find the vectors AB =a, AC=b and AD=c sharing the same initial point and use them as our basis vectors generating the parallelepiped. AB will be given by \( a = < x_2 – x_1, y_2 – y_1, z_2 – z_1 >\), Similarly we can find AC and AD.
Once we have vectors a, b, and c, follow these simple steps: Find the cross-product between the vectors \(\vec{a}\) and \(\vec{b}\) to get \(\vec{a}\times\vec{b}\).
Calculate the dot-product between the vectors \(\vec{a}\times\vec{b}\) and \(\vec{c}\) to get the scalar value \((\vec{a}\times\vec{b})\cdot\vec{c}\).
Determine the volume of the parallelepiped as the absolute value of this scalar, given by \(∣(\vec{a}\times\vec{b})\cdot\vec{c}∣\).
Sometimes you don’t know the vertices of the parallelepiped but the angles and side lengths are known:
To calculate the volume of a parallelepiped from its sides and angles we use the formula:
\(V = a{\cdot}b{\cdot}c{\cdot}\sqrt{(1 + 2{\cdot}cos({\alpha}){\cdot}cos({\beta}){\cdot}cos({\gamma}) – cos^2({\alpha}) – cos^2({\beta}) – cos^2({\gamma}))}\)
Where,
\(\alpha\) – Angle between the sides b and c;
\(\beta\) – Angle between the sides a and c; and
\(\gamma\) – Angle between the sides a and b.
Area of Parallelepiped is the sum of the area of all its surfaces. This is called the total surface area of the parallelepiped. When it comes to area 3D objects there are two important surface areas:
Learn about the area of quadrilateral.
Lateral Surface Area of a Parallelepiped
The lateral surface area of a parallelepiped is defined as the sum of the surface area of its faces excluding the base and the top. The Lateral Surface Area (LSA) of a Parallelepiped is equal to the product of the perimeter of the base and the height of the Parallelepiped.
Lateral surface area of a parallelepiped Formula: \(LSA= 2(a+b){\times}c\)
Total Surface Area of a Parallelepiped
The total surface area of a parallelepiped is defined as the total region covered by all the faces of the shape.
Total surface area of a parallelepiped Formula: \(TSA=2(ab+bc+ac)\)
In vector form, we can write it as,
\(A = 2{\times}(∣\vec{a}{\times}\vec{b}∣ + ∣\vec{b}{\times}\vec{c}∣ + ∣\vec{a}{\times}\vec{c}∣)\)
Where,
\(∣\vec{a}{\times}\vec{b}|: Magnitude \; of \; the \; cross-product \; between \; \vec{a}\) and \(\vec{a}\)
\(∣\vec{b}{\times}\vec{c}|: Magnitude \; of \; the \; cross-product \; between \; \vec{b}\) and \(\vec{c}\)
\(∣\vec{c}{\times}\vec{a}|: Magnitude \; of \; the \; cross-product \; between \; \vec{c}\) and \(\vec{b}\)
There is an alternative way to calculate the area of a parallelepiped using its side lengths \(a\), \(b\) and angles. It is given by the formula
\(A = 2\times(a{\cdot}b{\cdot}sin(\gamma) + b{\cdot}c{\cdot}sin(\alpha) + a{\cdot}c{\cdot}sin(\beta))\), where:
\(\alpha\) – Angle between b and c;
\(\beta\) – Angle between a and c; and
\(\gamma\) – Angle between a and b.
A rectangular parallelepiped is a polyhedron with six faces, which is also known as a hexahedron. It is a three-dimensional parallelepiped structure whose all six faces are in rectangular shape and the length of the parallel edges are equal. It is a special case of the parallelepiped. A rectangular parallelepiped is analogous to a 2D rectangle.

Learn about rectangles.
The formula of a rectangular parallelepiped includes the formula for its surface area, volume and diagonals.
Surface Area of Rectangular Parallelepiped
There are six rectangles in the Rectangular Parallelepiped figure. We must calculate the area of six rectangles in order to determine their surface area (faces). The surface area formula is given by:
Surface Area \(= 2(l{\times}h) + 2(l{\times}w) + 2(h{\times}w)\)
\(S = 2[(l{\times}h) + (l{\times}w) + (h{\times}w)]\)
where
\(l\), \(w\), \(h\) are the length, width, height of the rectangular parallelepiped respectively.
Lateral Surface Area of Rectangular Parallelepiped
The product of base perimeter and height is known as lateral surface area. Each face of a rectangular parallelepiped figure is a rectangle, making the base’s perimeter equal to the rectangle’s perimeter. The following is the formula for LSA (Lateral Surface Area):
LSA = Perimeter of base × Height
As the perimeter of the base is equal to 2(length + breadth)
= 2(length + breadth) × Height
\(LSA = 2lh + 2wh\)
where
\(l\), \(w\), \(h\) are length, width and height of the rectangular parallelepiped respectively.
The area of the base multiplied by the height yields the volume of a rectangular parallelepiped. The base of a rectangular parallelepiped is a rectangle, just like each of its faces, and its area is equal to the product of its length and width. The volume formula is as follows:
Volume = area of base × height
\(V = l{\times}w{\times}h\)
Diagonal Length of Rectangular Parallelepiped
Let \(d\) be the length of the body diagonal of a rectangular parallelepiped having length, width and height as \(l\), \(w\) and \(h\), then this length is given by:
\(d=\sqrt{l^2+w^2+h^2}\)
Some important solved examples on Parallelepiped are given below:
Example 1: Find the total surface area of the given parallelepiped if length is 13 cm, breadth is 12 cm and height is 10 cm.
Solution: We know that,
Total Surface Area (TSA) = 2(ab + bc + ac), here a = 13 cm, b = 12 cm, c = 10 cm
= 2(13 × 12 + 12 × 10 + 10 × 13 )
= 812 sq.cm
Example 2: Consider a parallelepiped ABCDEFGH with edge lengths a = 7, b = 5, and c = 3. If ∠DAE=45°, ∠BAD=63°, and ∠BAE=50°, then what is the surface area of the parallelepiped?
Solution: Here,
\(\alpha=∠BAD=63°\) – Angle between b and c;
\(\beta=∠DAE=45°\) – Angle between a and c; and
\(\gamma=∠BAE=50°\) – Angle between a and b.
The surface area will be given by, would be given by
\(A = 2\times(a{\cdot}b{\cdot}sin(\gamma) + b{\cdot}c{\cdot}sin(\alpha) + a{\cdot}c{\cdot}sin(\beta))\)
\(A = 2\times(7{\cdot}5{\cdot}sin(50) + 5{\cdot}3{\cdot}sin(63) + 7{\cdot}3{\cdot}sin(45))\)
\(A = 2\times(35{\cdot}sin(50) + 15{\cdot}sin(63) + 21{\cdot}sin(45))\)
\(A = 110.05\) sq. units
Example 3: Find the volume of a parallelepiped with vectors a = (1, 1, 2), b = (2, 1, 3) and c = (3, 1, 2).
Solution: Volume of a parallelepiped is given by the determinant of the matrix:
\( V=
{\begin{bmatrix}
c_1 & c_2 & c_3\\
a_1 & a_2 & a_3\\
b_1 & b_2 & b_3
\end{bmatrix}}
\)
Substituting the values we get
\( V=
{\begin{bmatrix}
3 & 1 & 2\\
1 & 1 & 2\\
2 & 1 & 3
\end{bmatrix}}
\)
Finding the determinant we get,
\(V = |3(1\times3 – 2\times1) – 1(1\times3 – 2\times2) + 2(1\times1 – 1\times2)|\)
\(V = |3\times1 – 1\times(-1) + 2\times(-1)|\)
\(V = 2 \) cube units.
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