20 Sep turtle.isvisible() function in Python
The turtle.isvisible() function returns True if the turtle is visible, False if it is hidden.
Syntax: turtle.isvisible()
Parameters: None.
Let us see an example to implement the turtle.isvisible() function in Python:
Demo40.py
# turtle.isvisible() function in Python
# Code by Studyopedia
import turtle
window = turtle.Screen()
t = turtle.Turtle()
print("Turtle is visible:", t.isvisible())
t.hideturtle()
print("Turtle is visible:", t.isvisible())
window.exitonclick()
The following is the output:

In the above code, we followed the below steps:
- Import module: import turtle loads the turtle graphics library.
- Create screen: window = turtle.Screen() opens the drawing window.
- Create turtle: t = turtle.Turtle() creates the turtle you’ll control.
- Check visibility (initial): print(“Turtle is visible:”, t.isvisible()) prints whether the turtle cursor is visible; initially this is typically True.
- Hide turtle: t.hideturtle() hides the turtle cursor (drawing behavior doesn’t change).
- Check visibility (after): print(“Turtle is visible:”, t.isvisible()) prints the updated state, now False.
- Close on click: window.exitonclick() waits for a mouse click, then closes the window.
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