18 Aug Java Program to check for Integer Overflow

Checking for Integer Overflow means adding a value to the maximum value. For Integer, we will increment by 1 to the Integer.MAX_VALUE. On incrementing, an error won’t be visible. However, the output will be Integer.MIN_VALUE.

Maximum value of Integer is 2³¹ – 1 i.e.

2147483647

Minimum value of Integer is 2³² i.e.

-2147483648

Example

Following is an example to check for Integer Overflow:

public class Example {

  public static void main(String[] args) {
   
   int a = Integer.MAX_VALUE;

   System.out.println("Maximum value of Integer = "+a);
   
   // incrementing Maximum value of Integer
   int i = a + 1;
   System.out.println("Incrementing Maximum value of Integer = "+i);

   long k = (long)i;

      if (k > a) {
          throw new ArithmeticException("Integer Overflow!");
      }
  }
}

Output

Maximum value of Integer = 2147483647
Incrementing Maximum value of Integer = -2147483648

On incrementing MAX_VALUE, it results in MIN_VALUE for Integer type in Java as shown above. Java handles overflow accordingly for Integer type.