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Ilina Ivanova
Ilina Ivanova
Last Activity: Oct 18 '10, 12:48 PM
Joined: Oct 7 '10
Location: Bulgaria
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  • Thank you, NeoPa! It`s really work! Thank you very, very much! It was so usefully joining the Bytes.com Expert Community!
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  • I have one table [Status] with four columns (ID, PB1, PB2, PB3) (the data in the other fields is not relevant to my question and I removed it). I want to create a query [Index] showing the ID in one column and the average of PB1,PB2,PB3 in second column. I have difficulties to build the expression for average because there are records with missing values and I need the sum to be divided by 2 or 1. Zero is a value too....
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  • Sorry NeoPa. I`ve tried many times including copy/paste after your recommendation but without any result. The expression disappears after I run the query or a message of incorrect subquery`s syntax appears.
    Is it possible to e-mail you the file for help me.
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  • Thank you, NeoPa,
    I`ve tried it, but it is impossible to run the query because of message „ ... the query does not include the specified expression „ID” as a part of an aggregate function”.
    I am a beginner in Access and probably I make a mistake.
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  • Ilina Ivanova
    started a topic How to calculate the average of columns

    How to calculate the average of columns

    I have a DB (Access 2007) with 4 columns. The first is the ID of the patient and the others are indexes PB1 , PB2, PB3. I have difficulties to calculate the average of columns PB1, PB2, PB3, because when 2 fields are filled the average needs to be divided by 2. Zero is a value too.
    Thanks!
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    Last edited by Niheel; Oct 7 '10, 07:15 AM.

  • Ilina Ivanova
    started a topic How to calculate the average of columns

    How to calculate the average of columns

    Please, help me!
    I have a DB (Access 2007) with 4 columns. The first is the ID of the patient and the others are indexes PB1 , PB2, PB3. I have difficulties to calculate the average of columns PB1, PB2, PB3, because when 2 fields are filled the average needs to be divided by 2. Zero is a value too.
    Thanks!
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