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Atrisa
Last Activity: Jun 5 '11, 07:19 PM
Joined: Sep 17 '10
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User-Agent browser info
Hi everyone. I want to get list of browsers from the User-Agent strings in HTTP header. The browser info is said to be the second entry inside the parenthesis (U for Mozilla Firefox), but sometimes that is not enough and it must be related to other entries, like in the following where the browser is Google Chrome and seen second last in the string.
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I could solve the problem by usinginstead ofCode:netloc
and then some manual parsing. Thanks bvdet.Code:hostname
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I changedtoCode:urlparse(ref).hostname
, now it neither gives error nor prints anything. Is there anything else that could do what I wantCode:urlparse(ref).netloc
to do?Code:hostname
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How to fix error "'NoneType' object has no attribute 'split'"?
I have a file with lines like this:
...Code:Host: gateway.edge.messenger.live.com Referer: 13.gateway.edge.messenger.live.com/help Host: ads.lfstmedia.com Referer: http://facebook.mafiawars.com:80/? Host: gateway.edge.messenger.live.com Referer: 13.gateway.edge.messenger.live.com/help Host: ads.lfstmedia.com Referer: 13.gateway.edge.messenger.live.com/help Host: ads.google.com
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Thanks dwblas. For some reason it kept telling me that score is not defined, though it is. After making some changes, now the working code looks like this:
thanks a lot again,Code:scoreDict.setdefault(ID, 0) scoreDict[ID] += int(score)
AtrisaLeave a comment:
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In a dictionary, sum values if similar keys
Hi everyone. I have a file of records like this:
ID:13
Date: 12.12
Scores: 2
ID:22
Date: 9.12
Scores: 4
ID:13
Date: 18.12
Scores: 4
I want to have the unique IDs as keys and the sum of the socres for that ID as values in the scoreDict dictionary. This is my code so far:
...Code:if ID is not None: if ID not in scoreDict: -
Thanks BV for your hints, helps and instructions:)Leave a comment:
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Now it is working.
Code:dd = {} for line in open('test.txt'): if line.startswith('Writer'): writer = line.split(':')[1].strip('\n') dd.setdefault(writer, 0) dd[writer] += 1 print ddLeave a comment:
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Still the dictionary is empty.Leave a comment:
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This is what I did, but don't know why it doesn't print anything:
Code:f = open('test.txt').read() dd = {} for line in f.split('\n\n'): if line.startswith('Writer'): writer = line.split(':')[0] dd.get(writer, 0) dd[writer] += 1 print ddLeave a comment:
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How to loop through previous lines
Hi everyone. I have a text file looking like this:
Book ID: 1
Availability: on shelf > 3 borrows > 2
Name: Bread and Wine
Writer: Silone
Book ID: 2
Availability: on shelf > 4 borrows > 1
Name: Fontamara
Writer: Silone
Book ID: 3
Availability: on shelf > 3 borrows > 2
Name: Poirot
Writer: Agatha Christie
Book... -
Finally these are the line that did it:
Thanks bvdet for your help.Code:for key in dd.keys(): for item in ports_name.keys(): if key == item: outfile.write("\n".join(["%s %s %s" % (key, dd[key], ports_name[item])])+ "\n")Leave a comment:
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Now I get the port description in the third column of the output file 'capture25000-column3.txt', but each description is repeated for few times, not just once as the port numbers are. Some output:
25910 1 pangolin-laser
55149 1 pangolin-laser
4024 4 www-http
13734 2 www-http
2451 2 www-http
55617 6 iapp
61510 1 iapp
which is not correct. The few last lines of the following code...Leave a comment:
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Unfortunately that didn't work either. I changed few lines in the previously sent code this way:
and now the dictionary looks like this:Code:. . . port_table[port[0]]=line1[0] keycount +=1 content=f.readline() ports_name={} get_port_name ('Ports', ports_name)
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{'8732': 'dtp-net', '4026': 'as-debug',...Leave a comment:
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Now I have created the following method in the code that you did earlier. The method creates a dictionary that has the port numbers and their corresponding port names:
...Code:def get_port_name (name, port_table): # ports.txt is a file where I have put the IANA PORT NUMBERS f= open('ports.txt','r') content=f.readline() keycount=1 while content: key = str(keycount)Leave a comment:
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Thanks a lot bvdet for your help and your time. That works perfectly. It's two weeks that I have started learning Python, that's why I am a bit lost.Leave a comment:
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I also want to count how many times the port numbers appeared in the 'column3' and put the port number and beside it the number of appearances of that port in a file, so that I have something like this:
21283 3
21283 2
23479 1
80 7
10464 2
and so on. This is my code that tries to do that, but it gives me only 1 appearance for each port:
...Code:outfile
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Thanks a lot bvdet. That worked well:)Leave a comment:
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I first have an input file that has captured data. I need only the third column from that file, so I did it this way:
Then I get the list 'column3' which looks like this:Code:# for (i, eachline) in enumerate(open('capture25000.txt','r')): # column3 = eachline.split(' ')[2]
27.20.29.12.212 83
27.20.29.12.212 83
65.24.112.69.23 479
27.120.98.21.80
32.16.45.74.104 64
56.176.45.74.10 464...Last edited by bvdet; Sep 20 '10, 06:29 PM.Leave a comment:
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The actual data which is in a file called 'capture25000-column3.txt' is a set of port numbers like this:
52141
21283
43439
21283
21283
23479
80
10464
80
80
21283
43439
80
10464
10464
21283
.
.
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and there are 25000 rows of those numbers. If you need all of them, I could send it to your email.Leave a comment:
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