Python 2.3 problem

Re: Python 2.3 problem

There is way to few information in this mail, but I guess you meant the
following:

def pinhtranh(*args , laoc_te):
phnoi_crek(*arg s, laoc_te)

Note the *args on the second line.

Regards,
Florian

On Sun, 24 Aug 2003 22:00:01 +0200 (CEST), Nomen Nescio <[email protected] om>
wrote:
[color=blue]
> Hi
>
> When I does this like hear failre goes:
>
> def pinhtranh(*args , laoc_te):
> phnoi_crek(args , laoc_te)
>
> I do "laoc_te" last praemetr name always.
>
>
> Qinh
>
>
>[/color]



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Re: Python 2.3 problem

In article <51092f25c1b12d 2bedc9c63d2dfa1 [email protected]>, Nomen Nescio wrote:[color=blue]
> Hi
>
> When I does this like hear failre goes:
>
> def pinhtranh(*args , laoc_te):
> phnoi_crek(args , laoc_te)
>
> I do "laoc_te" last praemetr name always.
>[/color]


This is not allowed.

*args and **kwargs must come after the regular arguments.

Re: Python 2.3 problem

On Sunday 24 August 2003 01:00 pm, Nomen Nescio wrote:[color=blue]
> Hi
>
> When I does this like hear failre goes:
>
> def pinhtranh(*args , laoc_te):
> phnoi_crek(args , laoc_te)
>
> I do "laoc_te" last praemetr name always.
>
>
> Qinh[/color]

The syntax of Python does not allow this, but perhaps the following
will do what you want. The two lines in pinhtranh will set "laoc_te"
to the last argument, and "args" to a tuple of all except for the last
argument.

def pinhtranh(*allA rgs):
args = allArgs[:-1]
laoc_te = allArgs[-1]
...

I hope that's what you wanted.

Gary Herron