Python problem

Re: Python problem

WIWA wrote:[color=blue]
>
> I'm trying to write the following in python:[/color]
[color=blue]
> j=0
>
> for i in range(len(datum lijst)+1):
> if (datumlijst[i+1]!=datumlijst):
> datum[j]=datumlijst
> j=j+1[/color]
[color=blue]
> print datum[:]
>
> it complains about the part: datumlijst[i+1]!=datumlijst
>[/color]
You are comparing a list with a list entry which is probably unintended.
[color=blue]
> datum[j]=datumlijst
>
> IndexError: list assignment index out of range
>[/color]
You seem to assume that a list grows automatically. That's not true in
Python.

Now here's my guess of your intentions:

datumlijst = [1,1,2,2,3,4,5,5 ,5,5,6,3]
datumlijst.sort ()
datum = [datumlijst[0]]

for i in range(len(datum lijst)-1): # all list indexes start with 0
if datumlijst[i+1] != datumlijst[i]: # both indexed
datum.append(da tumlijst[i+1]) # note the append()

print datum #no need for [:]

There may still sit a bug in the above. The following should be a little
more robust, e. g. no need to sort datumlijst, no extensive use of list
indexes:

from sets import Set
datumlijst = [1,1,2,2,3,4,5,5 ,5,5,6,3]
print list(Set(datuml ijst))

This is Python 2.3 only, in 2.2 you can do it with a dictionary, using the
keys only.

Peter

PS: I see you've already fallen in love with whitespace :-)