String Manipulation

Re: String Manipulation

| I need a piece of code that takes a string like this
| string1 = "aaa/bbb/ccc/dd" and extracts a string containting
| the character after the last "/"
|
| So for this example the result would be "dd"
| ...

lamar_air ...

Here is one way ...

[color=blue][color=green][color=darkred]
>>> str_in = 'aaa/bbb/ccc/dd'
>>>
>>> list_in = str_in.split( '/' )
>>>
>>> last_element = list_in[ -1 ]
>>>
>>> print last_element[/color][/color][/color]
dd[color=blue][color=green][color=darkred]
>>>[/color][/color][/color]


--
Cousin Stanley
Human Being
Phoenix, Arizona

Re: String Manipulation

John Hunter wrote:
[color=blue][color=green][color=darkred]
>>>>>>"lamar" == lamar air <lamar_air@hotm ail.com> writes:[/color][/color]
>
>
> lamar> I need a piece of code that takes a string like this
> lamar> string1 = "aaa/bbb/ccc/dd" and extracts a string
> lamar> containting the character after the last "/"
>
> One good way to do this is to split the string on the '/' character,
> which creates a list of strings
>[color=green][color=darkred]
> >>> string1 = "aaa/bbb/ccc/dd"
> >>> parts = string1.split('/')
> >>> parts[/color][/color]
> ['aaa', 'bbb', 'ccc', 'dd']
>
> Now you just want to get the last element of this list; python allows
> you to index with -1 to get the last element, -2 to get the second to
> last, etc...
>[color=green][color=darkred]
> >>> parts[-1][/color][/color]
> 'dd'
>
> JDH
>[/color]

While is is perfectly acceptable, you might want to consider another
solution if it is *path names* you are manipulating:
[color=blue][color=green][color=darkred]
>>> import os
>>> os.path.split(" aaa/bbb/ccc/dd")[/color][/color][/color]
('aaa/bbb/ccc', 'dd')[color=blue][color=green][color=darkred]
>>> os.path.split(" aaa/bbb/ccc/dd")[1][/color][/color][/color]
'dd'


because this will work correctly on other platforms too when the
path separator is not '/'.

--Irmen de JOng

Re: String Manipulation

I know a few people replied to this already, but here's one additional
possibility. If the data in string1 is a file path for your platform,
then you can use the os.path module.
[color=blue][color=green][color=darkred]
>>> import os.path
>>> os.path.split(" aaa/bbb/ccc/dd")[/color][/color][/color]
('aaa/bbb/cc', 'dd')[color=blue][color=green][color=darkred]
>>> os.path.splitex t("filename.ext ")[/color][/color][/color]
('filename', '.ext')

The other suggestions will of course work, but if you data is a file
path, then using the os.path module should be a more portable solution.

Brandon



"lamar_air" <lamar_air@hotm ail.com> wrote in message
news:2c6431ab.0 307151223.4173c [email protected] gle.com...[color=blue]
> I need a piece of code that takes a string like this string1 =
> "aaa/bbb/ccc/dd" and extracts a string containting the character after
> the last "/"
>
> So for this example the result would be "dd"
>
> like this:
> for i=0; string1.right(i ) != '/'; i++
>
> result = string1.mid(i, string1.length( ))
>
> but in python.[/color]

Re: String Manipulation

On Tue, Jul 15, 2003 at 01:58:09PM -0700, Cousin Stanley wrote:[color=blue]
> | I need a piece of code that takes a string like this
> | string1 = "aaa/bbb/ccc/dd" and extracts a string containting
> | the character after the last "/"
> |
> | So for this example the result would be "dd"
> | ...
>
> lamar_air ...
>
> Here is one way ...
>
>[color=green][color=darkred]
> >>> str_in = 'aaa/bbb/ccc/dd'
> >>>
> >>> list_in = str_in.split( '/' )
> >>>
> >>> last_element = list_in[ -1 ]
> >>>
> >>> print last_element[/color][/color]
> dd[color=green][color=darkred]
> >>>[/color][/color]
>
>
> --
> Cousin Stanley
> Human Being
> Phoenix, Arizona
>[/color]

In Unix,
[color=blue][color=green][color=darkred]
>>> os.path.basenam e("aaa/bbb/ccc")[/color][/color][/color]
'ccc'

Inyeol

Re: String Manipulation

On 15 Jul 2003 13:23:09 -0700, lamar_air@hotma il.com (lamar_air) wrote:
[color=blue]
>I need a piece of code that takes a string like this string1 =
>"aaa/bbb/ccc/dd" and extracts a string containting the character after
>the last "/"
>
>So for this example the result would be "dd"
>
>like this:
>for i=0; string1.right(i ) != '/'; i++
>
>result = string1.mid(i, string1.length( ))
>
>but in python.[/color]

Others have posted the split() solutions.
You could also search backward in Python:
[color=blue][color=green][color=darkred]
>>> s = "aaa/bbb/ccc/dd"
>>> s[s.rfind('/')+1:][/color][/color][/color]
'dd'[color=blue][color=green][color=darkred]
>>> s='no_slashes'
>>> s[s.rfind('/')+1:][/color][/color][/color]
'no_slashes'

Regards,
Bengt Richter

Re: String Manipulation

On 15 Jul 2003 19:51:56 -0700, [email protected] m.ernet.in (Vinoo Vasudevan) wrote:
[color=blue]
>lamar_air@hotm ail.com (lamar_air) wrote in message news:<2c6431ab. 0307151223.4173 [email protected] ogle.com>...[color=green]
>> I need a piece of code that takes a string like this string1 =
>> "aaa/bbb/ccc/dd" and extracts a string containting the character after
>> the last "/"
>>
>> So for this example the result would be "dd"
>>
>> like this:
>> for i=0; string1.right(i ) != '/'; i++
>>
>> result = string1.mid(i, string1.length( ))
>>
>> but in python.[/color]
>
>How about this:
>string1 = 'aaa/bbb/ccc/dd'
>result = string1[string1.rfind('/')+1:]
>
>Hope it's helpful,[/color]
Sorry Vinoo, for some reason your post did not show up for me before I posted
the same solution, even though your post is dated much before mine.
I guess it has to do with delays in news servers forwarding and such.

Regards,
Bengt Richter