__eq__ and __ne__

I was surprised by the following behavior. Apparently, the "!="
operator does not fall back to using "not __eq__()". I tested this with
Python 2.1, 2.2, and 2.2 with new-style classes and got the same results
in every case.
[color=blue][color=green][color=darkred]
>>> class foo:[/color][/color][/color]
.... def __eq__(self, other):
.... return (other.__class_ _ is self.__class__
.... and other.__dict__ == self.__dict__)
....[color=blue][color=green][color=darkred]
>>> foo() == foo()[/color][/color][/color]
1[color=blue][color=green][color=darkred]
>>> foo() != foo()[/color][/color][/color]
1

I would expect the second test to yield "0". To compensate, I've
started adding the following boilerplate code to all classes that define
only __eq__:

def __ne__(self, other):
return not self.__eq__(oth er)

Does this surprise anyone else? I have not yet found documentation on this.

Shane