Closures with functions as parameters

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  • limweizhong
    New Member
    • Dec 2006
    • 62
    #1

    Closures with functions as parameters

    Hi,

    Could anyone explain what happens when some function (x) is passed as a parameter into a function (b) which is nested inside a function(a), i.e.
    Code:
    a=function()
{
  b=function(t)
  {
    // what scope chain does t have in here?
  };
  b(x); // where x is some random function that could be externally defined.
};
    Last edited by Dormilich; Sep 27 '11, 04:12 PM. Reason: please use [CODE] [/CODE] tags when posting code
    Tags: argument, closure, function, parameter
    • Dormilich
      Recognized Expert Expert
      • Aug 2008
      • 8694
      #2
      hm, I don’t see anything special (functions are like any other variables) so I’d say the standard rules apply.

      edit: btw, you code is not a closure.
      Last edited by Dormilich; Sep 27 '11, 04:24 PM.

        Comment

        • limweizhong
          New Member
          • Dec 2006
          • 62
          #3
          Thanks for clarifying. I originally thought that running the parameter t as a function inside b would allow me to get to the variables inside a, or perhaps if t returns a function, that function would inherit the variables inside a. However, after some testing, I have found that it is incorrect.

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