A couple language questions

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  • Ken Kast
    #1

    A couple language questions

    1) I want to test for the existence of a method o.m(), so I tried the line
    if (o.m) ...
    but the interpreter objects to the missing parentheses on m. (This is in
    IE.) What is an appropriate approach for checking the existing of a
    function?

    2) I've got the following code
    window.onresize = function {
    ....
    f();
    }
    function f() {
    ....
    }
    <BODY onload="f();">

    My question: if the resize event happens while f is executing, is the first
    call to f (onload) flushed from the stack? If not, where in f is execution
    resumed after the second call to f takes place in response to the resize
    event?

    Thanks.

    Ken


    Tags: None
    • Janwillem Borleffs
      #2
      Re: A couple language questions


      "Ken Kast" <[email protected] m> wrote in message
      news:be1h4t$mjk [email protected] hgrum.com...[color=blue]
      > 1) I want to test for the existence of a method o.m(), so I tried the line
      > if (o.m) ...
      > but the interpreter objects to the missing parentheses on m. (This is in
      > IE.) What is an appropriate approach for checking the existing of a
      > function?
      >[/color]

      if (typeof o == 'object' && typeof o.m == 'function') {
      // Function exists
      }
      [color=blue]
      > 2) I've got the following code
      > window.onresize = function {
      > ...
      > f();
      > }
      > function f() {
      > ...
      > }
      > <BODY onload="f();">
      >[/color]

      window.onresize = f; // this is sufficient
      [color=blue]
      > My question: if the resize event happens while f is executing, is the[/color]
      first[color=blue]
      > call to f (onload) flushed from the stack? If not, where in f is[/color]
      execution[color=blue]
      > resumed after the second call to f takes place in response to the resize
      > event?
      >[/color]

      My guess is that the function will be called twice after the calls have been
      queued.


      JW



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