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What is the equation of the line in point-slope form that passes through the points 4 8 and 2 -2?
Points: (4, 8) and (2, -2) Slope: (8--2)/(4-2) = 5 Equation: y-8 = 5(x-4) => y = 5x-12 Equation: y--2 = 5(x-2) => y = 5x-12 So straight line equation is: y = 5x-12
What is X plus y equals 12. And -x equals -y-10?
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What are 2 integers whose product is -72 and whose sum is 6?
ANSWER: 12 and -6x * y = 72x = 72/y Equation 1x + y = 6 Equation 2Substitute Eq.1 to Eq.2-72/y + y = 6multiply both sides of the equation by yy (-72/y + y ) = 6* y-72 + y2 = 6yy2 - 6y - 72 = 0(y- 12) (y + 6) = 0y = 12 ; y = -6x =-12 ; x = 12Take x = 12 and y = -6
What is the range of the equation y equals x - 4 times 2 plus 12?
y = x - 4 × 2 + 12 y = x - 8 + 12 y = x - 20 That is the simplest form of the equation, as you can only solve completely by having only 1 variable to solve.
How do you solve x4-6x2-12?
To solve the equation ( x^4 - 6x^2 - 12 = 0 ), you can make a substitution by letting ( y = x^2 ). The equation then becomes ( y^2 - 6y - 12 = 0 ). You can solve this quadratic equation using the quadratic formula ( y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ). After finding the values of ( y ), substitute back ( y = x^2 ) to find the values of ( x ).
What is the equation for y plus 2 equals 12?
The equation is y + 2 = 12.
What is the answer to this equation y plus 2 equals 12?
y = 10
What is the equation of the line in point slope form that passes through the points (4 8)and (2 -2)?
Points: (4, 8) and (2, -2) Slope: (8--2)/(4-2) = 5 Equation: y-8 = 5(x-4) => y = 5x-12 Equation: y--2 = 5(x-2) => y = 5x-12 So straight line equation is: y = 5x-12
What is the equation of the line in point-slope form that passes through the points 4 8 and 2 -2?
Points: (4, 8) and (2, -2) Slope: (8--2)/(4-2) = 5 Equation: y-8 = 5(x-4) => y = 5x-12 Equation: y--2 = 5(x-2) => y = 5x-12 So straight line equation is: y = 5x-12
What is the equation of the line in point-slope form that passes through the points (-7 -10) and (-6 -8)?
Points: (4, 8) and (2, -2) Slope: (8--2)/(4-2) = 5 Equation: y-8 = 5(x-4) => y = 5x-12 Equation: y--2 = 5(x-2) => y = 5x-12 So straight line equation is: y = 5x-12
What sum of two numbers is 12 and their difference is 2 Find the numbers?
5 & 7 Solution: x+y = 12 x-y = 2 => x = y+2 Substitute the x in the first equation with the second equation: (y+2) + y = 12 2y = 10 y = 5 x = 7
How do you write an equation out of these words 8 more than the quotient of y and 12 is 2?
y/12 + 8 = 2
What is X plus y equals 12. And -x equals -y-10?
2
How do you do math substitution?
Mathematical substitution is the process of using one equation to solve for multiple variables. For example: Equation 1: x + y = 4 Equation 2: 2x + y = 16 Using equation 1, solve for y: y = 4 - x <-- Plug this into equation 2. This is substitution because you are replacing y in equation 2 with what y is equal to in equation 1. 2x + y = 16 ----> 2x + (4 - x) = 16 Now you can solve for x: x + 4 = 16; x = 12 You can then substitute the value of x back into the equation that is solved for y: y = 4 - 12; y = -8 Check both equations: Equation 1: -8 + 12 = 4; 4 = 4 (Correct) Equation 2: 2(12) + (-8) = 16; 24 - 8 = 16; 16 = 16 (Correct) We have successfully used substitution to solve for two different variables, x and y.
What are 2 integers whose product is -72 and whose sum is 6?
ANSWER: 12 and -6x * y = 72x = 72/y Equation 1x + y = 6 Equation 2Substitute Eq.1 to Eq.2-72/y + y = 6multiply both sides of the equation by yy (-72/y + y ) = 6* y-72 + y2 = 6yy2 - 6y - 72 = 0(y- 12) (y + 6) = 0y = 12 ; y = -6x =-12 ; x = 12Take x = 12 and y = -6
What is the y-intercept of -2x 2y x 12?
The equation -2x=2y*12 is first simplified to y = ((-2x)/12)/2 y = -2x/24 y = -x/12 The graph is then graphed and the equation intersects the y-axis at y = 0. So the y-intercept is 0.
What is the range of the equation y equals x - 4 times 2 plus 12?
y = x - 4 × 2 + 12 y = x - 8 + 12 y = x - 20 That is the simplest form of the equation, as you can only solve completely by having only 1 variable to solve.
How do you solve x4-6x2-12?
To solve the equation ( x^4 - 6x^2 - 12 = 0 ), you can make a substitution by letting ( y = x^2 ). The equation then becomes ( y^2 - 6y - 12 = 0 ). You can solve this quadratic equation using the quadratic formula ( y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ). After finding the values of ( y ), substitute back ( y = x^2 ) to find the values of ( x ).
Which equation is equivalent to y plus 12 equals -3 open parenthesis x-2 close parenthesis?
y + 12 = -3(x - 2) y + 12 = -3x + 6 y = -3x - 6 or y = -3(x + 2)
What is the equation for a circle with a center of 3.0 and a radius of 12?
(x-3)^2-(y-3)^2=(12)^2
What is the slope of the line represented by the equation y - 6 2(x plus 3)?
If you mean: y-6 = 2(x+3) then y = 2x+12 whereas 2 is the slope and 12 is the y intercept
What is the equation for a circle with a center of 3 0 and a radius of 12?
center (3,0) radius 12 So the equation is (x-3)^2 + y^2 = 144 → y^2 + x^2 - 6x - 135 = 0 in general a circle of radius r centered at (h, k) has the equation: (x - h)^2 + (y - k)^2 = r^2
The vertex of a parabola is (-2 -20) and its intercept is (0 -12).?
To find the equation of the parabola, we can use the vertex form, which is (y = a(x - h)^2 + k), where ((h, k)) is the vertex. Substituting the vertex ((-2, -20)), the equation becomes (y = a(x + 2)^2 - 20). Using the intercept ((0, -12)) to find (a), we substitute (x = 0) and (y = -12), resulting in (-12 = a(0 + 2)^2 - 20). Solving for (a) gives (a = 2), leading to the final equation (y = 2(x + 2)^2 - 20).
What are the two numbers whose sum is twelve and whose difference between their squares is forty eight?
4 & 8 Watch me closely. X + Y = 12 AND X^2 - Y^2 =48 Solve 1st equation for X ; X = 12 - Y Substitute into 2nd equation [12 - Y]^2 - y^2 = 48 144 - 24Y + Y^2 - Y^2 = 48 144 - 24Y = 48 24Y = 96 Y = 4 and X = 8
What is the point slope equation of (-3-2)(12)?
Points: (-3, -2) and (1, 2) Slope: 1 Equation: y = x+1
