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How many ounces of a ten percent alcohol solution must be mixed with 6 ounces of a fifteen percent alcohol solution to make a thirteen percent alcohol solution?
4 ounces
How many ounces of a 25 percent alcohol solution must be mixed with 9 ounces of a 30 percent alcohol solution to make a 28 percent alcohol solution?
Let a be the number of ounces of 25% alcohol required. Then, 25a + (30x9) = 28(9 + a) 25a + 270 = 252 + 28a 3a = 18 a = 6 Then 6 ounces of 25% alcohol + 9 ounces of 30% alcohol produces 15 ounces of 28% alcohol.
What does it mean when 6 percent of you kidney is functioning?
6%
How much water should be added to four liters of 75 percent alcohol to make a mixture of 30 percent alcohol?
There are 3 litres of alcohol in your starting mixture of 4 litres. If you add 6 litres of water you will have 3 litres of alcohol in a total of 10 litres. This is the required strength.
How many gallons each of 25 percent alcohol and 35 percent alcohol should be mixed to obtain 20 gallons of 32 percent alcohol?
The question is best solved using basic algebra. You need 20 gallons of 32% alcohol. This will contain 0.32*20 = 6.4 gallons of pure alcohol. Now suppose you have X gallons of 25% alcohol in the mixture. That contains 0.25X gallons of pure alcohol. Also, since you have 20 gallons in total, you must have 20-X gallons of the 35% alcohol. This will contain 0.35*(20-X) = 7 - 0.35X gallons of pure alcohol. Then, the total amount of pure alcohol is 0.25X + 7 - 0.35X = 7 - 0.1X gallons. So you have 7 - 0.1X = 6.4 or 0.6 = 0.1X or X = 6. So the answer is 6 gallons of 25% alcohol and 14 gallons of the stronger stuff!
