multiply it by itself and then multiply that by the original number. example: 2 cubed. 2*2=4 4*2=8
27, whose cube is 19683
729
729
8 cubed = 512
1
27, whose cube is 19683
729
729
27
8 cubed = 512
729, cube of 9 and square of 27
In some circumstances yes
-1
1
It is: 1,000,000
729
729
729
203 = 8000, so the first digit is 2, and the second digit must be 1 (because only 13 =1). So the cube root of 9261 is 21.
"Taking a cube" is the same basic procedure, whether it's a one-digit number, a three digit number, a complex number, a square matrix, or anything else you can multiply. Taking the cube simply means, multiply the number by itself, in such a way that it appears three times as a factor. For example, if your three-digit number is 235, you calculate the cube as 235 x 235 x 235.
46*46*46 = 97336
88
I am pretty sure you can figure this out on your own. Raise different numbers to the square, until you get a 4-digit result. Similary, calculate the cube of different numbers, until you get a 4-digit number. If you want the SAME number to be both a perfect square and a perfect cube, then it must be a power of 6. In that case, just experiment raising different numbers to the sixth power, until you get a 4-digit number.
6859
6