No - the sum of any two rational numbers is still rational:
Any, and every, irrational number will do.
The sum of two irrational numbers may be rational, or irrational.
It is always an irrational number.
Yes.
Let `a` be a rational number and `b` be an irrational number,assume that the sum is rational. 1.a +b =c Where a and c are rational and b is irrational. 2.b=c-a Subtracting the same number a from each side. 3.b is irrational c-a is a rational number we arrived at a contradiction. So the sum is an irrational number.
The sum of a rational and irrational number must be an irrational number.
No. In fact the sum of a rational and an irrational MUST be irrational.
The value of the sum depends on the values of the rational number and the irrational number.
It is always irrational.
The sum is irrational.
Such a sum is always irrational.
An irrational number.
The sum of the three can be rational or irrational.
Any, and every, irrational number will do.
Since the sum of two rational numbers is rational, the answer will be the same as for the sum of an irrational and a single rational number. It is always irrational.
The sum of two irrational numbers may be rational, or irrational.
It is always an irrational number.
Yes
Yes.
It is always an irrational number.
Wrong. It is always an irrational number.
Yes.
Let R1 = rational number Let X = irrational number Assume R1 + X = (some rational number) We add -R1 to both sides, and we get: -R1 + x = (some irrational number) + (-R1), thus X = (SIR) + (-R1), which implies that X, an irrational number, is the sum of two rational numbers, which is a contradiction. Thus, the sum of a rational number and an irrational number is always irrational. (Proof by contradiction)
Let `a` be a rational number and `b` be an irrational number,assume that the sum is rational. 1.a +b =c Where a and c are rational and b is irrational. 2.b=c-a Subtracting the same number a from each side. 3.b is irrational c-a is a rational number we arrived at a contradiction. So the sum is an irrational number.
The sum of a rational and an irrational number is always irrational. Here is a brief proof:Let a be a rational number and b be an irrational number, and c = a + b their sum. By way of contradiction, suppose c is also rational. Then we can write b = c - a. But since c and a are both rational, so is their difference, and this means that bis rational as well. But we already said that b is an irrational number. This is a contradiction, and hence the original assumption was false. Namely, the sum c must be an irrational number.