It is 2w.
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2 x 2 x 13 x w
w=2*pi*sqr(x/t) First divide each side by 2*pi w/(2pi)=sqr(x/t) Next square both sides (w/2pi)^2=x/t Next multiply both sides by t t(w/2pi)^2=x
Let x be L, so W = x - 2 P = 2(L + W) substitute 28 for P, x for L, and x - 2 for W; 28 = 2(x + x - 2) divide by 2 to both sides; 14 = 2x - 2 divide by 2 to both sides; 7 = x - 1 add 1 to both sides; 8 = x x - 2 = 8 - 2 = 6 So L = 8 cm and W = 6 cm. A = LW = 8 x 6 = 48 Thus the area is 48 cm^2
w/2 - 18 = - 7 Add 18 to both sides of the equation w/2 = - 7 + 18 w/2 = 11 Multiply both sides by 2 w = 11 x 2 w = 22
if width is equal to W and length is equal to L, then W x L = 80 L = W +2 so W x (W+2) = 80 solve to find W=8 and L= 10