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3 is in the hundreds place
I think the answer is 612!1 (tens digit) which is odd is half of 2 (hundreds digit) and the sum is (6+1+2=9).
10 times for the one's digit, 1-100 10 times for the ten's digit, 60-70 = 20 times
start with the 100's place 0 = 0+0 1 = 1+0 = 0+1 2 = 1+1=2+0=0+2 3 = 3+0 = 2+1 = 1+2 = 0+3 ... with the 100's digit, the number of such numbers is one greater than that number 0 : 1 1 : 2 ... therefore there are 1+2+3+4+5+6+7+8+9+10 = 5*11 = 55 such numbers unless you don't count 000 as a three digit number, then there are 54 such numbers.