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Oh, isn't that a happy little question? Let's see here... To find the number of combinations of 4 numbers out of 7, we can use a simple formula: 7 choose 4, which is calculated as 7! / (4! * (7-4)!). So, there are 35 unique combinations of 4 numbers that can be made from a set of 7 numbers. Isn't that just delightful?
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How many combinations of 6 can be made from the numbers 0 to 9?
(9 x 8 x 7 x 6 x 5 x 4)/(6 x 5 x 4 x 3 x 2) = 84 combinations.
How many combinations of 6 numbers are there in 10 numbers?
The answer is 10!/[6!*(10-6)!] where n! represents 1*2*3*...*n Number of combinations = 10*9*8*7*6*5*4*3*2*1/(6*5*4*3*2*1*4*3*2*1) = 10*9*8*7/(4*3*2*1) = 210
How many combinations of 6 in 8?
(8 x 7 x 6 x 5 x 4 x 3)/(6 x 5 x 4 x 3 x 2) = 28 combinations
How many different two digit numbers can you form using the digits 1 2 3 5 6 7 and 9 with repetition?
7*7 = 49 numbers.7*7 = 49 numbers.7*7 = 49 numbers.7*7 = 49 numbers.
List of all 4 digit combintions without repeating using only numbers 0-9?
Oh, dude, you wanna list out all the 4-digit combinations without repeating digits from 0 to 9? That's like 10 choose 4, which is 10! / (4!(10-4)!), which equals 210. So, there are 210 unique 4-digit combinations you can make using numbers 0 to 9 without repeating any digits. Cool, right?
