How to sort a Python dictionary by multiple values

See How to sort a Python dictionary by key or value for how to sort a Python dictionary at all.

Let's say we have the following dictionary and we want to sort it first in descending order by price, then in ascending order by name of the fruit or vegetable. Higher priced items would come first, and in the case of a tie, the results would be alphabetized.

data = {
    "bananas": {
        "count": 3, "price": 0.50
    },
    "apples": {
        "count": 5, "price": 0.25
    },
    "cucumbers": {
        "count": 10, "price": 0.75
    },
    "artichokes": {
        "count": 13, "price": .25
    }
}

We follow the same principles as in the first TIL, but after item:, we pass a tuple of elements instead of a single element.

>>> sorted_data = dict(sorted(data.items(), key=lambda item: (-item[1]["price"], item[0])))

>>> print(sorted_data)
{
    'cucumbers': {
        'count': 10, 'price': 0.75
    },
    'bananas': {
        'count': 3, 'price': 0.5
    },
    'apples': {
        'count': 5, 'price': 0.25
    },
    'artichokes': {
        'count': 13, 'price': 0.25
    }
}

The - in front of item[1]["price"] indicates that we want this element sorted in descending order. We see that the results of the dictionary are sorted by price from highest to lowest. In the case of a price tie (like with apples and artichokes), the results are alphabetical.