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Is there an equivalent to numpy fft.irfft? #71

@FrankHileman

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@FrankHileman

Thank you to produce this library. Does it contain an equivalent to numpy fft.irfft? I did find the complex inverse.
https://numpy.org/doc/stable/reference/generated/numpy.fft.irfft.html

I am a C# programmer, so I understand how to convert from in-place to generating a new array.

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