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Strange test name #151
Description
Python 3.6.8
pytest-6.1.2
cases-2.5.0
Test flask application
test_file
@pytest.fixture
def barToFoo():
app.config["foo"]["bar"] = "foo"
yield
app.config["foo"]["bar"] = "bar"
@parametrize_with_cases("inputs,request_data", prefix="case_create_")
@pytest.mark.usefixtures("clearMongo", "mocked_oid", "mocked_uuid")
def test_create(db, flaskClient, inputs, request_data):
...
db, flaskClient, clearMongo, mocked_oid, mocked_uuid - fixtures
case file
class CreateCases(object):
@case(id="simple")
def case_create_2(self, barToFoo):
inputs = ["foo", "bar"]
request_data = {"foo": "dfg", "data": "asd"}
return inputs, request_data
Test name is test_create[inputs_request_data_is_simple]. Without fixture barToFoo in params case_create_2, test name is test_create[simple].
How do i get the name test_create[simple] with fixture barToFoo?
Activity
smarie commentedon Dec 2, 2020
Thanks @arut-grigoryan for this feedback.
Well this is actually a limitation of the implementation.
when all cases do not require any fixture, a
@parametrizedecorator is created with argvalues set as a list oflazy_values, each referring to a case. Since none of them is a fixture_ref,@parametrizedefaults topytest.parametrizeand the ids correspond to the "simple" version.when at least one case requires a fixture, a new fixture is created for that case. The
@parametrizedecorator created under the hood will in this situation receive in its argvalues at least onefixture_ref(for that case) instead of alazy_value. In that case the pytest implementation does not support it because this is a "fixture union" (in some parameters you need a - possibly parametrized - fixture, while in some others you don't). So in that case@parametrizecreates a fixture union with several "branches" or so-called "alternatives". An additional parameter is added to the parametrization to describe this branching. This parameter has by default an id schema following the pattern "is". This is why you get an id of inputs_request_data_is_simple.Now there is a workaround if you wish to forget that there is a new fixture created behind the scenes: symply set
idstyle=Noneoridstyle='nostyle'.I added a test for your case just as a reference, and updated the documentation. Let me know if this looks sufficient to you (feel free to reopen the ticket if this is not).
I admit that this sounds complex, but fixture unions are complex, actually. I try my best to hide this complexity and auto-simplify things when possible but sometimes I was not able to find an elegant simplification, in particular for the ids.
See also here for a detailed explanation on fixture unions