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Spent a lifetime on that because I had not noticed that I was first enumerating elements using a list L, then enumerating the same elements using {x:i for i,x in enumerate(L)}. And of course that was not the same ordering T_T
Nathann
CC: @videlec
Component: combinatorial designs
Author: Nathann Cohen
Branch/Commit: dee4275
Reviewer: Vincent Delecroix
Issue created by migration from https://trac.sagemath.org/ticket/16797
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