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Cannot pickle numpy.datetime64 scalars in Python 3.6 #11656
Description
Reproducing code example:
Using numpy==1.15.0 and Python 3.6
import pickle
import numpy as np
pickle.dumps(np.datetime64('2016-01-01T00:00:00.000000000'))
leads to BufferError: could not get scalar buffer information
Numpy/Python version information:
>>> import sys, numpy; print(numpy.__version__, sys.version)
1.15.0 3.6.4 | packaged by conda-forge | (default, Dec 23 2017, 16:54:01)
[GCC 4.2.1 Compatible Apple LLVM 6.1.0 (clang-602.0.53)]
Activity
tylerjereddy commentedon Aug 3, 2018
I bisected to identify the problematic commit:
adaag commentedon Aug 8, 2018
@xhochy
def parallel_apply(data, fun, args):
pool = mp.Pool(mp.cpu_count() - 1)
result = [pool.apply(fun, (data.loc[x, :], *args)) for x in data.index]
result = [p.get() for p in result]
end_result = pd.concat(result)
return end_result
from this part of code i also get following error "BufferError: could not get scalar buffer information". i tried several things to solve it but non of them worked. Any sugesstion? Thanks for help
Ape commentedon Aug 20, 2018
Is there a release planned that would contain this fix?
eric-wieser commentedon Aug 20, 2018
:)