TypeScript Version: 3.8.2-dev.201xxxxx

Search Terms: call apply overload

Code

interface Fn {
  (x: string): void;
  (x: number, y: boolean): void;
}

declare const f: Fn;
f(''); // ok
f.call(null, ''); // error 
f.apply(null, ['']); // error

Expected behavior:
No type errors as f('') is equivalent to f.call(null, '') and f.apply(null, ['']).

Actual behavior:
Type errors on f.call(null, '') and f.apply(null, ['']).

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