Replacing a regex with a quick character check #3308
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tlhunter
commented
Aug 8, 2017
tlhunter
commented
- Checking the 0th position of the string should be quicker than a regular expression
* Checking the 0th position of the string should be quicker than a regular expression
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jdalton
reviewed
Aug 8, 2017
| const result = [] | ||
| if (reLeadingDot.test(string)) { | ||
| if (string.charAt(0) === '.') { | ||
| result.push('') |
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Comparing against the char code would be faster.
Something lile
const codeOfDot = '.'.charCodeAt(0)Then later
string.charCodeAt(0) === codeOfDot
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Closing as inactive. |
falsyvalues
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jdalton
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jdalton
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This was referenced Apr 19, 2018
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