Chaining map and reverse returns unmodified array. #890
Description
When upgrading to 3.0.0 I had trouble with a code block very similar to
_([{a: 1}, {a: 2}, {a: 3}, null])
.map(function(v) { return v && v.a })
.compact()
.reverse()
.value()resulting in [1, 2, 3, null], where I had expected [3, 2, 1].
Comparing this example with the following you'll see that while the values can change the order and index will remain the same.
// returns [1, 2, 3, null], expected [null, 3, 2, 1]
_([1, 2, 3, null]).map(_.identity).reverse().value()
// returns [1, 2, 3, null], expected [3, 2, 1]
_([1, 2, 3, null]).map(_.identity).compact().reverse().value()