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command/grub2-set-default.md

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grub2-set-default
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===
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设置系统默认的启动内核
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## 语法
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```shell
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Usage: grub2-set-default [OPTION] MENU_ENTRY
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Set the default boot menu entry for GRUB.
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This requires setting GRUB_DEFAULT=saved in /etc/default/grub.
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-h, --help print this message and exit
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-v, --version print the version information and exit
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--boot-directory=DIR expect GRUB images under the directory DIR/grub2
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instead of the /boot/grub2 directory
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MENU_ENTRY is a number, a menu item title or a menu item identifier.
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Report bugs to <[email protected]>.
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```
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## 实例
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查看可选的系统内核:
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```shell
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# awk -F\' '$1=="menuentry " {print $2}' /etc/grub2.cfg
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CentOS Linux (5.4.219-1.el7.elrepo.x86_64) 7 (Core)
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CentOS Linux (3.10.0-1160.76.1.el7.x86_64) 7 (Core)
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CentOS Linux (3.10.0-862.el7.x86_64) 7 (Core)
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CentOS Linux (0-rescue-3221d376917c458992a952d6327f2d6a) 7 (Core)
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```
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grub2-set-default后面的序号从0开始。所以,如果想设置第一个选项为默认启动内核,则可以使用下面的命令:
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```shell
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# grub2-set-default 0
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```
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如果想使用CentOS Linux (3.10.0-862.el7.x86_64) 7 (Core)内核版本,则可以将0改为2
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重启系统
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```shell
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~]# init 6
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```

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