Environment details
- Working with google maps tile overlays
- OS: MacOS 15.5 (24F74)
- Library version: 6.6.0
Steps to reproduce
- Setup a
TileOverlay with a TileProvider and a rememberTileOverlayState()
- Recompose with a different
TileProvider
tileOverlayState.clearTileCache() do not do anything anymore (it's attached to a TileOverlay that was removed)
Code example
@Composable
fun Content() {
GoogleMap(
modifier = Modifier.fillMaxSize(),
) {
UpdatedTileOverlay()
}
}
@Composable
fun UpdatedTileOverlay() {
var tileProviderIndex by remember { mutableIntStateOf(0) }
var renderedIndex by remember { mutableIntStateOf(0) }
val state = rememberTileOverlayState()
val size = with(LocalDensity.current) { 256.dp.toPx() }.toInt()
val tileProvider = remember(tileProviderIndex) {
TileProvider { x, y, zoom ->
Tile(size, size, renderTiles(renderedIndex, size))
}
}
TileOverlay(tileProvider = tileProvider, state = state, fadeIn = false)
LaunchedEffect(Unit) {
repeat(5) {
delay(1000)
renderedIndex += 1
state.clearTileCache()
}
// update the tile provider
tileProviderIndex += 1
while (true) {
delay(1000)
renderedIndex += 1
state.clearTileCache()
}
}
}
fun renderTiles(index: Int, size: Int): ByteArray {
val bitmap = createBitmap(size, size)
val canvas = Canvas(bitmap)
canvas.drawText(index.toString(), (size / 2).toFloat(), (size / 2).toFloat(), Paint().apply {
color = Color.Black.toArgb()
textSize = 100f
})
val outputStream = ByteArrayOutputStream()
bitmap.compress(Bitmap.CompressFormat.WEBP_LOSSLESS, 0, outputStream)
return outputStream.toByteArray()
}Expected behavior
- When recomposing a tile overlay, the tile overlay in the
remember(ed)TileOverlayState should be updated.
- With the above sample: the rendered number on the tiles should keep increasing forever (cache clearing would trigger re-rendering with the new number).
Actual behavior
- When
TileProvider is updated on recomposition (not the initial composition), a new tile overlay is created but not linked to the TileOverlayState (only done in onAttached on TileOverlayNode which is not called in that case)
