[Java.Interop] Emit a reference assembly for Java.Interop.dll (#716)

jonathanpeppers · web-flow · commit 6cde08775fbe · 2020-09-17T20:55:17.000-04:00
Context: dotnet/android@00c2c1a The `Microsoft.Android.Ref` package for .NET 6 needs to contain reference assemblies for each assembly we ship. `Java.Interop.dll` is one of the assemblies included in the `Microsoft.Android.Ref` package, so we need to set `$(ProduceReferenceAssembly)`=True so that a reference assembly is created automatically. Size difference: Length Name ------ ---- 227328 Java.Interop.dll 94208 ref/Java.Interop.dll
diff --git a/src/Java.Interop/Java.Interop-MonoAndroid.csproj b/src/Java.Interop/Java.Interop-MonoAndroid.csproj
@@ -15,6 +15,7 @@
     <SignAssembly>true</SignAssembly>
     <AssemblyOriginatorKeyFile>..\..\product.snk</AssemblyOriginatorKeyFile>
     <LangVersion>8.0</LangVersion>
+    <ProduceReferenceAssembly>true</ProduceReferenceAssembly>
   </PropertyGroup>
   <Import Project="..\..\Directory.Build.props" />
   <PropertyGroup Condition=" '$(Configuration)|$(Platform)' == 'Debug|AnyCPU' ">
diff --git a/src/Java.Interop/Java.Interop.csproj b/src/Java.Interop/Java.Interop.csproj
@@ -14,6 +14,7 @@
     <JNIEnvGenPath>$(BuildToolOutputFullPath)</JNIEnvGenPath>
     <LangVersion>8.0</LangVersion>
     <Nullable>enable</Nullable>
+    <ProduceReferenceAssembly>true</ProduceReferenceAssembly>
   </PropertyGroup>
   <PropertyGroup Condition=" '$(Configuration)|$(Platform)' == 'Debug|AnyCPU' ">
     <DefineConstants>DEBUG;$(DefineConstants)</DefineConstants>
