Callable type has no attribute __name__ #2375
Description
Summary
Consider this short snippet:
from concurrent.futures import Future, ProcessPoolExecutor
from typing import Callable, ParamSpec, TypeVar
P = ParamSpec("P")
T = TypeVar("T")
class ProcessPoolManager:
def __init__(self, max_workers: int):
self.max_workers: int = max_workers
self.__executor = ProcessPoolExecutor(max_workers=self.max_workers)
def submit_job(self, fn: Callable[P, T], *args: P.args, **kwargs: P.kwargs) -> Future[T]:
future = self._executor.submit(fn, *args, **kwargs)
future.add_done_callback(lambda f: self._handle_job_completion(f, fn.__name__))
return futureWith pyright/basedpyright, I don't get any type warnings (it seems the assume callable is a named function). But with ty I get the following:
> ty check test.py
error[unresolved-attribute]: Object of type `(**P@submit_job) -> T@submit_job` has no attribute `__name__`
--> test.py:15:75
|
13 | def submit_job(self, fn: Callable[P, T], *args: P.args, **kwargs: P.kwargs) -> Future[T]:
14 | future = self._executor.submit(fn, *args, **kwargs)
15 | future.add_done_callback(lambda f: self._handle_job_completion(f, fn.__name__))
| ^^^^^^^^^^^
16 |
17 | return future
|
help: Function objects have a `__name__` attribute, but not all callable objects are functions
info: rule `unresolved-attribute` is enabled by default
Found 1 diagnostic
The help message is very useful here, and I see that it is probably right. But I can't figure out how to either change my signature to only allow "named" functions or how to adjust so that we only get __name__ if it is available. I was hoping someone here might have an idea?
Version
> ty version
ty 0.0.9